When would the normal force not equal the weight?

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SUMMARY

The normal force does not always equal the weight of an object due to additional forces acting in the vertical direction. For instance, when an upward force is applied to an object, the normal force adjusts to equal the gravitational force minus the applied force. Additionally, on a frictionless slope, the normal force only counters the component of gravity perpendicular to the slope, allowing the object to slide down. Situations such as stacking books demonstrate how the weight of an object can affect the normal force experienced by another object beneath it.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Basic knowledge of forces and free-body diagrams
  • Familiarity with gravitational force calculations (Fg=mg)
  • Concept of normal force in physics
NEXT STEPS
  • Study the effects of applied forces on normal force in static equilibrium
  • Explore the mechanics of frictionless surfaces and inclined planes
  • Investigate scenarios involving multiple objects and their interactions (e.g., stacking)
  • Review pulley systems and their impact on normal force dynamics
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of forces and motion in static and dynamic systems.

gungo
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Homework Statement


I know that on a horizontal surface. if the net force is 0 in the y direction the weight of object=the normal force, but wouldn't the normal force always equal the magnitude of gravity on an object, just in opposite directions? Because if the weight is stronger than the normal force or vice versa, the object would move in the y direction, but objects don't fall through the ground or randomly or start floating so I'm kind of confused.

Homework Equations


Fg=mg

The Attempt at a Solution


N/A
 
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Assuming a statics situation ##\sum \mathbf F = 0##, there are conceivable situations in which the normal force wouldn't equal the force of gravity. One example is if you were applying a light upward force on the object from a hand or string or something that isn't strong enough to actually pick it up. In this case, the normal force would equal the force of gravity minus the applied upward force.
 
gungo said:

Homework Statement


I know that on a horizontal surface. if the net force is 0 in the y direction the weight of object=the normal force, but wouldn't the normal force always equal the magnitude of gravity on an object, just in opposite directions? Because if the weight is stronger than the normal force or vice versa, the object would move in the y direction, but objects don't fall through the ground or randomly or start floating so I'm kind of confused.

Homework Equations


Fg=mg

The Attempt at a Solution


N/A
Normal force between two surfaces is the minimum magnitude force which prevents their interpenetration. Thus, it is always normal to the contact plane.
If an object is placed on a frictionless slope, the normal force only has to counter the component of gravity normal to the plane. The other component leads the object to slide down.

See also https://www.physicsforums.com/insights/frequently-made-errors-vectors-elementary-use and https://www.physicsforums.com/insights/frequently-made-errors-mechanics-friction/
 
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