- #1
BiBByLin
- 17
- 0
A 1-D metal put inside a E0 electric field just like shown in following figure.
--> |- <-- +| -->
--> |- <-- +| -->
--> |- <-- +| --> E0
--> |- <-- +| -->
--> |- <-- +| -->
Suppose the positive charge density of δ1, the negative charge density δ2, δ1=-δ2.
The inducing electric field Ei=Epos+Eneg=-2δ1/ε0
Eloc=Ei+E0=0
so, δ1=δ1*ε0/2
for positive side, using Guass's Law,
∮E*ndA=q/ε0
the E inside the metal equals to 0.
So, Eout=q/dA*1/ε0=ε0/ε0=1/2E0
but it should be E0
Where am I wrong.
--> |- <-- +| -->
--> |- <-- +| -->
--> |- <-- +| --> E0
--> |- <-- +| -->
--> |- <-- +| -->
Suppose the positive charge density of δ1, the negative charge density δ2, δ1=-δ2.
The inducing electric field Ei=Epos+Eneg=-2δ1/ε0
Eloc=Ei+E0=0
so, δ1=δ1*ε0/2
for positive side, using Guass's Law,
∮E*ndA=q/ε0
the E inside the metal equals to 0.
So, Eout=q/dA*1/ε0=ε0/ε0=1/2E0
but it should be E0
Where am I wrong.