Where Does the Energy Go in a Capacitor Without Resistance?

AI Thread Summary
When a capacitor is charged by a battery with no resistance, the work done by the battery equals C*E^2, while the stored energy in the capacitor is (C*E^2)/2, leading to a discrepancy. This raises the question of where the "lost" energy goes, with some suggesting it could be related to the kinetic energy of the charges. However, the discussion concludes that a model without resistance is not physically realistic. In practical scenarios, resistance plays a crucial role in energy transfer and storage. Overall, understanding energy dynamics in capacitors requires considering real-world conditions, including resistance.
Yegor
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The capacitor of capacitance C is charged by battery (emf = E) (assume that there is no resistance). In the end charge of the capacitor Q = C*E; Work done by the battery W = Q*E=C*E^2. But The energy of charged capacitor is U = (C*E^2)/2. Work doesn't equals to stored energy. Where we lost energy?? Can we forget about kinetic energy of the charges it this case?? Or it is exactly that "lost" energy?
 
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Thank you very much. As i understood, the model without resistance isn't really physical. With nonzero resistance everything is ok.
 
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