Where Does the Energy Go in Atomic Collisions?

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In atomic collisions, energy is transferred between atoms rather than solely converting to heat, which is a macroscopic concept not directly applicable to microscopic interactions. The second law of thermodynamics does not mandate that all work done during collisions must become heat; some energy can remain in the atoms themselves. Additionally, energy may be radiated as electromagnetic radiation, which can be perceived as heat on a larger scale. The misunderstanding arises from misapplying macroscopic thermodynamic principles to atomic-level events. Ultimately, energy in atomic collisions is conserved and redistributed rather than entirely dissipated as heat.
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Hey, I know I'm wrong, but I don't know where. I've read several textbooks and searched the web, I would appreciate if you could explain my mistake:

When two atoms collide with each other, they would do work on each other. By the second law of thermodynamics, some of this work would turn to heat, which will dissipate. Eventually, all of the atom's energy would convert to heat, and the atoms would stop moving. This is clearly not happening, so what's wrong?
 
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godingly said:
Eventually, all of the atom's energy would convert to heat, and the atoms would stop moving.
Heat is the movement of atoms.
 
The second law of Thermodynamics doesn't require any of the work to convert to heat. More importantly though you are trying to a apply a macroscopic concept - heat - to a microscopic collision. Where do you supposed the energy of the collision will go, if not the atoms themselves? Some of it may be radiated as electromagnetic radiation (That would be considered heat from a macroscopic point of view), but there is no contradiction there.
 
Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
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