Where is the 5.50 N force applied along the meter stick?

AI Thread Summary
A meter stick is pinned at one end, allowing it to rotate freely while two forces are applied to maintain a net torque of zero. One force of 1.90 N is applied perpendicularly at the free end, while a second force of 5.50 N is applied at a 27-degree angle. The discussion revolves around determining the position along the stick where the 5.50 N force is applied, measured from the pinned end. The original poster resolved the issue independently and found solutions to both the torque problem and an additional question. The thread highlights the importance of understanding torque and force application in rotational dynamics.
Adanne
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One end of a meter stick is pinned to a table, so the stick can rotate freely in a plane parallel to the tabletop. Two forces, both parallel to the tabletop, are applied to the stick in such a way that the net torque is zero. One force has a magnitude of 1.90 N and is applied perpendicular to the length of the stick at the free end. The other force has a magnitude of 5.50 N and acts at a 27 degree angle with respect to the length of the stick. Where along the stick is the 5.50 N force apllied? Express this distance with respect to the end that is pinned.
 
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sorry about that, but I figured out the problem on my own and the other question i had too.
 

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