Where is the Center of Gravity of a Lying Person?

AI Thread Summary
The discussion revolves around calculating the center of gravity of a 160cm tall person lying on a board supported by two scales. The scales read 29.4kg under the feet and 32.8kg under the head, prompting a torque analysis to find the center of mass. Participants suggest using the person’s midpoint as a pivot point for torque calculations, with initial torque values computed incorrectly due to unit confusion. After clarification, the correct torques are calculated using meters instead of centimeters. The conversation emphasizes the importance of accurate unit conversion and the correct application of torque principles in physics.
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Homework Statement



A 160cm tall person lies on a light(massless) board which is supported by two scales , on under the feet and the beneath the top of the head. the scale under his feet read 29.4kg
and the scale under his head reads 32.8 kg ... where is the center of gravity of this person??

Homework Equations





The Attempt at a Solution

 
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What have you tried so far? It's always a good idea to start with a picture and a force-body diagram.
 
the simplest method to solve the problem is to calculate net torque abt the center of mass of person [take it as xi^+ yj^] from both the sides.then calculate the difference in the torques to get the value which gives the distance from the center of mass.

first proceed with the first step and update me of the progress.
 
huh ? i don't understand
 
what u mean is ... take the torques from each side ... and use the very middle of the person as the pivot point? am i correct ?
if so i got
t1 = 32.8 * 80
= 2624
t2=29.4 * 80
= 2352
does that look right??
 
comeon..how can you take the distance as 80 cm??

take it as .80m

the new relations are;

t1=.80*32.8
=26.24

t2=29.4*80=23.52
 
yah alright i get that ... next step??
 
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