Where is x^3 + 12x + 5 increasing and decreasing

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SUMMARY

The function f(x) = -x^3 + 12x + 5 is analyzed for intervals of increase and decrease within the range -3 < x < 3. The critical points are determined by setting the first derivative, f'(x) = -3x^2 + 12, to zero, yielding x = ±2. The function is increasing on the intervals (-3, -2) and (2, 3) and decreasing on the interval (-2, 2). To confirm whether these points are local maxima or minima, the second derivative test is applied.

PREREQUISITES
  • Understanding of calculus concepts, specifically derivatives
  • Familiarity with first and second derivative tests for extrema
  • Knowledge of polynomial functions and their properties
  • Ability to analyze function behavior within specified intervals
NEXT STEPS
  • Study the first derivative test for identifying increasing and decreasing intervals
  • Learn about the second derivative test for classifying local extrema
  • Explore polynomial function behavior and characteristics
  • Practice finding critical points and analyzing function graphs
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Students studying calculus, mathematics educators, and anyone interested in understanding function behavior and optimization techniques.

teng125
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Find intervals on which f(x)=-x^3 + 12x +5 , -3<x<3 is increasing and decreasing. Where does the function assume extreme values and what are these values ?

does anybody knows how to do this??
 
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I have the feeling derivatives may be a good idea :smile:

Do you know a necessary and/or sufficient condition for extrema, using derivatives?
 
no,pls explain to me
 
When a function becomes extreme in a point, the tangent line will be horizontal there which means that the derivative of the function is 0 there. Note that this is a one-way argument, an extremum implies a zero derivative but not the other way arround, so this is a necessary condition - though not sufficient.

To check whether it is actually a min or max, you can use the second derivative or investigate whether the function switches from increasing to decreasing or vice versa arround that point.
 

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