Whether an increased voltage accelerates the electrons

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    Electrons Voltage
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SUMMARY

An increased voltage does accelerate electrons in a circuit, leading to a higher current flow. Current, defined as the rate of flow of charge carriers, increases with voltage according to Ohm's Law, represented by the formula I = V/R. While electrons move slowly, their drift velocity increases with higher voltage, resulting in a net flow of charge carriers. The propagation of the electric field, which initiates current flow, travels at speeds near that of light, allowing for instantaneous circuit response.

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  • Understanding of Ohm's Law (I = V/R)
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tor2006
Whether the increased voltage accelerates the electrons since the current of one ampere is one coulomb of charge going past a given point per second, it seems to me somehow the most logical. but I'm interested in the opinion of others on that topic.
 
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tor2006 said:
Whether the increased voltage accelerates the electrons since the current of one ampere is one coulomb of charge going past a given point per second, it seems to me somehow the most logical. but I'm interested in the opinion of others on that topic.
Just as an aside on this question, you should NOT be interested in "the opinion of others", you should be interested in a factual answer. Science is not based on opinions.
 
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tor2006 said:
Whether the increased voltage accelerates the electrons since the current of one ampere is one coulomb of charge going past a given point per second, it seems to me somehow the most logical. but I'm interested in the opinion of others on that topic.
An increased voltage would accelerate the electrons, but don’t think of them zipping around the wires like race cars. In an ordinary conductor, electrons are jiggling randomly. If a current starts to flow, the random jiggling develops a net vector in the direction of flow. It’s more of a general drift of the order of mm/s.

I remember an argument with a friend’s dad when I was at school - he said the electrons must be moving ultra fast because when you switch a light on, it comes on instantaneously regardless of the length of lead. Point is, the ‘signal’ to start the current flow, ie the propagation of the electric field, travels at or near the speed of light. Think of a long hose already filled with water - turn the tap, and the flow starts as soon as the pressure pulse gets to the end - you don’t have to wait for the water to travel all the way along the hose.

If you want a (surprisingly detailed) account of electronic theory, try Practical Electronics for Inventors.
 
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In a circuit yes. The charge carriers in the wires are electrons.

Let us imagine a series circuit consisting of:
1. A voltage source.
2. In series with a resistor.

## I_{series} = \dfrac{ V_{source} }{ R_{1} } ##

in the standard model of any electric circuit with some components, an increased voltage increases the current in the circuit. Current is defined as being the rate of flow of charge carriers.
If more charge carriers are flowing past an imaginary plane in a section of wire before the terminal of the ressitor, then indeed the speed of charge carriers, has increased.

In fact, there is a relationship between current and drift velocity.
https://en.wikipedia.org/wiki/Drift_velocity
So, you are right, under certain conditions of course.

Again, current is defined as the flow of charged particles at a point or plane. If current increases, then the flow of charge carriers has increased.

So, technically, the flow of charge in a series circuit is the same, ie . the speed of the charge carriers (electrons) is the same in a series circuit. But in a parallel circuit, the flow of these charge carriers (electrons) differs, as current in branches is different.

Resistance is also defined as opposition to flow of charge. But charges move very slowly, about a few CM or MM (i don't remember) in a circuit. It is the energy transfer that is faster.
But of course, in an alternating current, charges fluctuate or jump around back and forth.
 
See the explanation in Wiki:

"
The formula for evaluating the drift velocity of charge carriers in a material of constant cross-sectional area is given by:[1]

{\displaystyle u={j \over nq},}
0861f4aa0a0b6e6aa7826a679b37db5b45df72d6

where u is the drift velocity of electrons, j is the current density flowing through the material, n is the charge-carrier number density, and q is the charge on the charge-carrier.

In terms of the basic properties of the right-cylindrical current-carrying metallic ohmic conductor, where the charge-carriers are electrons, this expression can be rewritten as[citation needed]:

{\displaystyle u={m\;\sigma \Delta V \over \rho ef\ell },}
5a0506eaf51270406014279ba0b10273ff016321

where

"
 

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