Which Boiling Point is Higher: Hex+Prop vs Prop? URGENT!

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SUMMARY

The boiling point of a mixture of hexane (C6H14) and propanone (acetone, CH3C=OCH3) is lower than that of pure propanone due to the disruption of dipole-dipole interactions by hexane molecules. Hexane has a boiling point of 68.7 degrees Celsius, while propanone has a boiling point of 56.5 degrees Celsius. The mixture's boiling point is influenced by the presence of lone pair electrons in propanone, which creates dipole-induced dipole interactions when mixed with hexane. This phenomenon is relevant in the study of phase equilibrium and azeotropes.

PREREQUISITES
  • Understanding of molecular interactions, specifically dipole-dipole and dipole-induced dipole forces
  • Familiarity with the boiling points of hexane and propanone
  • Knowledge of phase equilibrium concepts
  • Basic chemistry skills for interpreting molecular structures and compositions
NEXT STEPS
  • Research the concept of azeotropes and their implications in distillation
  • Learn about phase diagrams and their relevance to boiling point variations
  • Explore the effects of molecular structure on boiling points in organic compounds
  • Investigate experimental methods for measuring boiling points and phase equilibria
USEFUL FOR

Chemistry students, laboratory researchers, and anyone studying organic compounds and their boiling point behaviors in mixtures.

KLscilevothma
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Boiling point, urgent !

Which of the following has higher boiling point?
1) Mixture of hexane and propanone
2) propapone
(consider their relative molecular mass and the forces of attraction between the molecules)

I think the mixture of hexane and propanone has a higher boiling point, as propanone has lone pair electrons, therefore the force between the molecules in the mixture is dipole-induced dipole, while the force exists between pure propanone molecules is instantaneous diple-induced dipole.

However my classmate told me the mixture has a lower boiling point and was confirmed by my teacher.

I hope I can get your answer in 3 to 4 hours, if not, it's ok and I'll treat this thread as a discussion. Thanks in advance.

PS. This question is for the theory part of my lab. report. Since the data obtained was ridiculous, that's why I need to know the fact.

PS2. I need to finish it in 4.5 hours.
 
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The boiling point of Propane is -42degrees
The boiling point of Hexane is 69 degrees

I think you might be right Mrs Kam
 
I think you might be right Mrs Kam
Mrs Kam ??! I'm not Mrs Kam.

Propane : C3H8
propanone : CH3C=OCH3

In fact, i need to draw a graph, variation of boiling point against % composition by volume haxane/propanone mixture. (This is an experiment on phase equilibrium)
 
Last edited:
acetone

hexane: 68.7
acetone: 56.5

sounds like a boring lab
 
The word "azeotrope" should appear somewhere in the background material for the lab. Prediction of "azeotropes" is a topic for the M&PS forum.
 
Originally posted by myself
I think the mixture of hexane and propanone has a higher boiling point, as propanone has lone pair electrons, therefore the force between the molecules in the mixture is dipole-induced dipole, while the force exists between pure propanone molecules is instantaneous diple-induced dipole.
Um..this is wrong. The force between molecules in pure propanone(acetone) is dipole-dipole interaction, since there are 2 lone pair electrons. The bond between molecules in pure hexane is instantaneous dipole-induced dipole. If they are mixed together, hexane molecules will destroy the dipole-dipole interaction between propanone molecules and to form a diple-induced dipole interatction.


Thanks for your help.
 

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