Which Graph Matches Each Energy Structure in a 3-Level System?

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SUMMARY

The discussion focuses on identifying the correct heat capacity graphs corresponding to three distinct energy levels in a thermal equilibrium system. The participant utilized the partition function, defined as Z=exp(-B.E_0)+exp(-B.E_1)+exp(-B.E_2), to derive the average internal energy and subsequently the heat capacity. The key conclusion is that only one graph exhibits a non-zero heat capacity at low temperatures, indicating a single energy level system. The remaining graphs can be matched to the other energy structures through similar analysis.

PREREQUISITES
  • Understanding of partition functions in statistical mechanics
  • Familiarity with heat capacity concepts and calculations
  • Knowledge of thermal equilibrium and its implications
  • Ability to interpret graphical data related to energy levels
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  • Study the derivation and application of the partition function in statistical mechanics
  • Learn about the relationship between heat capacity and temperature in thermodynamic systems
  • Explore graphical analysis techniques for interpreting energy level diagrams
  • Investigate the implications of thermal equilibrium on energy distributions
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Students and researchers in physics, particularly those focusing on statistical mechanics, thermodynamics, and energy systems analysis.

Kjkus
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Homework Statement


I uploaded a picture of the problem here: http://imgur.com/kD35ROl
Sorry about the norwegian text, the problem is this:
The three figures with red lines indicate three different energy levels of a system in thermal equilibrium with a reservoir of temperature T. The three plots are the corresponding heat capacities, the problem is assigning the graphs to the correct energy structure. The plots are all with the same reference temperature Theta, but different reference heat capacities C*

Homework Equations

The Attempt at a Solution


I tried calculating the partition function, and working from there. I got Z=exp(-B.E_0)+exp(-B.E_1)+exp(-B.E_2). From there I tried calculating the average internal energy by taking the logarithm of Z and differentiating with respect to beta (B). The heat capacity should then be the derivative of the average internal energy with respect to temperature, but this doesn't really help me solve the problem at all. I think I may be attacking this all wrong
 
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I guess it is possible to solve it with the partition function, but I would simply do it by looking at the plots. Just one graph has a non-zero heat capacity at very low temperature. There is just one energy level system that can correspond to that.
The other two can be found in the same way.
 

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