Which resistor produces the most heat?

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The discussion centers on determining which resistor generates the most heat in a circuit. The participant calculated the power output for each resistor using the formula P = I^2R and found that the 5-ohm resistor produced the highest wattage at 48.05W. There was some confusion regarding the calculation methods, with suggestions that simpler approaches could yield the same conclusion without extensive circuit analysis. Ultimately, it was agreed that the 5-ohm resistor indeed dissipates the most heat, confirming the initial calculations. The conversation highlighted the importance of understanding circuit principles and the relationships between voltage, current, and resistance.
  • #31
CWatters said:
If you mark up the drawing correctly and apply KVL you should get an equation like this..

+15 + 10 + 10 + ? = 0

where ? is the voltage across the current source. It's not going to be -15V.

PS...

KVL says the voltages around a loop sum to zero. I find I make far fewer errors if I always write an equation that explicitly adds up to zero (eg V1+V2+V3+V4 = 0) and avoid trying to guess the polarity and write something like V1 + V2 + V3 = -V4

:oops: Thx, I get it now. So e.g. going round the outside circuit from bottom left corner potentials are successively 0, -15, +20, +10. Over the current source current is in the direction of voltage increase not decrease.

But no one to say the resistance there is -35 Ω - if voltage across it changes, current is still 1 A. A non-ohmic element. (Nohmic? Gnomic?)

It just needs dropping a few mental habits leaned in circuits with constant voltage supplies.
 
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  • #32
epenguin said:
Thx, I get it now. So e.g. going round the outside circuit from bottom left corner potentials are successively 0, -15, +20, +10. Over the current source current is in the direction of voltage increase not decrease.

That's not what I get at all.

By bottom left corner I take it you mean the junction between the 20R and the 15R ?

You didn't say which way around you are going either and that changes the sign of all the voltages.

If you go clockwise you get +10 +10 -? +15 = 0 where ? is the voltage across the current source. Solve to give ? = -35V. As you are going clockwise that means the top end of the current source is +ve wrt the bottom.

If you go anti clockwise you get.. -15 + ? -10 -10 = 0. Solve to give ? = +35V. As you are going anti clockwise that means the top end of the current source is +ve wrt the bottom which is the same thing.

Power.jpg
 
  • #33
We are in substatial agreement now, I was going anti-clockwise just as far as the junction where the voltage is + 10 V same as the potential from battery, I.e. two routes to same point where you do a circuit in one direction, perhaps preferable but equivalent.
 

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