A triangle has legs on the positive x and y axes, and its hypotenuse passes through the point (2,1). Which such triangle has the smallest area.
The Attempt at a Solution
I know the area of a triangle is 1/2 b*h. And I know that is the area that I am trying to minimize. So I could write the equation as A = 1/2 x*y. And to minimize that I will have to take the derivative and set it equal to 0. In order to do that I must rewrite the equation in terms of x's or y's. This is where I am stuck.