What is the probability of odd versus even in a football game?

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The discussion centers on the probability of the total score in a football game being odd or even. Participants debate whether this probability is truly a 50/50 chance, given the specific scoring methods in football, such as touchdowns, field goals, and safeties. One argument suggests that since safeties are infrequent, the likelihood of an even score is higher. The conversation also touches on the potential for using actual NFL data to estimate these probabilities more accurately. Ultimately, the need for a mathematical approach or formula to analyze the scoring distribution is emphasized.
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Who can figure this one out?

The topic of discussion amongst my friends and I:

What is the probability of the sum of a football game landing on odd versus even.

My friends say that it is a simple 50/50 coin toss. My rebuttal is that while in football the only integers that can be achieved by one score are: 2 3 6 7 or 8 thus limiting the possibility
of a 50/50 ratio.

2 = safety
3 = field goal
6 = touchdown w/ missed PAT, or missed 2pt. conversion
7 = touchdown w/ made PAT
8 = touchdown w/ made 2pt. conversion

My Hypothesis: Since safeties are rarely scored in a football game, I believe that even has the advantage versus odd.

Now I have read some responses of unrelated topics, and there seems to be a high number of intelligent people subscribed to this forum. Everyone likes to 1-up the next guy, which is good thus creating a large field of answers.

Please approach this question with an open mind, and really give it some thought as I have not come to a conclusion on my own.
 
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you can skip the potentially difficult mathematical proof and go to nfl.com and start analyzing actual data.

Since safetys, touchdowns w/ no extra pts, and touchdowns w/ 2 points all are even scores, then they don't change the outcome unless they are the only scoring event in a game (an odd number plus 2,6 or 8 is still an odd number, and even number is still an even number) the only contributors are the odd number scores since it really depends on if there are an odd number of odd scores or not (i.e. touchdown w/ ep and fieldgoals, which are also the most common) so that makes it easieir to think about.

If I were you, id find an estimate of the probability of even vs odd using actual NFL scores, then make a a bunch of bets with your friends that gives you the slight edge (if in fact there is a difference between the two)
 


As i appreciate your response, I don't think it helps me much. I figured that if I analyzed actual NFL data that I would come up with a rough estimate. I just don't want to have to do that, so I asked if anyone knew a basic formula to figure it out. Can it be proved that it's not a 50/50% chance? I know this isin't a common question in this forum, but I ask if anyone can answer it.
 


Well, if we assumed that safeties, touchdowns (all 3 kinds separately), and field goals were 'rare events' with independent Poisson distributions, we could find the probabilities of even/odd. Actually we'd need only the chance of the 3 and 7 point ones.

If you can give us the *average* number of touchdown+PAT combinations in a game, plus the *average* number of field goals, we can calculate the probabilities for you.
 
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