Why Am I Struggling with Thermal Physics Calculations?

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SUMMARY

This discussion centers on the challenges faced in thermal physics calculations, specifically regarding the calculation of heat energy required to heat aluminum. The formula used is Energy = mC(delta)θ, where 'm' is mass, 'C' is the specific heat capacity (1200 J/kg-K for aluminum), and 'θ' is the temperature change. The participant seeks clarification on the specific heat value and requests resources for further study. Key resources provided include HyperPhysics for foundational concepts and specific heat tables.

PREREQUISITES
  • Understanding of basic thermal physics concepts
  • Familiarity with the formula Energy = mC(delta)θ
  • Knowledge of specific heat capacities of materials
  • Basic algebra for manipulating equations
NEXT STEPS
  • Review the specific heat capacity of common materials using the HyperPhysics tables
  • Practice thermal physics problems using the formula Energy = mC(delta)θ
  • Explore the concept of heat transfer and its applications in real-world scenarios
  • Study the differences between temperature scales (Celsius, Kelvin) and their implications in calculations
USEFUL FOR

This discussion is beneficial for students preparing for exams in thermal physics, educators seeking teaching resources, and anyone looking to strengthen their understanding of heat energy calculations and specific heat capacities.

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Hi..i was trying out some calculations i found on some site as practice for my exam this Friday and realized that i don't understand at all..
Everytime i tried something..my answers were wrong..

E.i

1. How much heat energy is needed to heat 4 kg of aluminium by 8 (degrees)C?

The answer:

1. Energy = mC(delta)θ = 4 x 1200 x 8 = 38400 J

I don't understand where the 1200 came from..

Can anybody give me links to thermal physics and general physics notes and/or worked examples for me to try out?
 
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It would help if one would write units with the numbers in a problem.


Energy = mC(delta)θ, where m is the mass (in this case 4 kg), C is specific heat (which is unique or specific to a material which would be in units of J/kg-K), and θ would be the temperature (in K or °C, and not to be confuse with an angle). Some people use T for temperature.


Here is a good site for some basic physics - http://hyperphysics.phy-astr.gsu.edu/hbase/hframe.html

and for the problem at hand - http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html

Table of specific heats - http://hyperphysics.phy-astr.gsu.edu/hbase/tables/sphtt.html#c1
Cp = 900 J/kg-K for Al in this table.


Please expend some effort and review the notes on Hyperphysics.

Thank you. :smile:
 

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