Bridge Card Game: Finding the Probability of Spades & One-Suit Hands

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In bridge, the probability of one player being dealt all 13 spades is calculated as 1 divided by the number of ways to choose any 13 cards from 52, represented as 1/(52C13). For the probability of a player holding a hand made up of only one suit, it is determined by the formula 4/(52C13), accounting for the four suits available. The discussion highlights a clarification that the probabilities refer to any player, not a specific one. Participants seek confirmation on the accuracy of these calculations. Understanding the context of "any one of the players" is crucial for interpreting the probabilities correctly.
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In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards.

(a)What is the probability that one of the players is dealt all the spades?
(b)What is the probability that one of the players holds a hand that is made up of only one suit?

(a) There is only one way to choose all 13 spades.
52C13 ways to choose any 13 cards
So, 1/(52C13)

(b) Since there are 4 different suits, the probability is 4/(52C13).

Does anyone know why my answers are wrong? Thanks.
 
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hihi davedave! :smile:
davedave said:
In the game of bridge, four players are dealt 13 cards each from a well-shuffled deck of 52 playing cards.

(a)What is the probability that one of the players is dealt all the spades?
(b)What is the probability that one of the players holds a hand that is made up of only one suit?

i think they mean any one of the players (ie, not a particular player) :wink:
 
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