Why are the objects the same speed at the finish line?

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Discussion Overview

The discussion revolves around the question of why two objects reach the same speed at the finish line despite potentially differing paths and distances traveled. It explores concepts related to net work, kinetic energy, and the forces acting on the objects, particularly in the context of a frictionless ramp.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants assert that the speed will be the same at the finish line, but this does not imply that the objects will arrive simultaneously, as one object travels a longer distance.
  • There is a suggestion that the net work done on both objects is the same, leading to the conclusion that their kinetic energies must also be the same, resulting in equal final velocities.
  • Participants discuss the role of gravity as the primary force doing work on the objects, especially in the context of a frictionless ramp.
  • One participant questions whether gravity is the only force acting on the objects and acknowledges the presence of a normal force, which they initially believe does no work.
  • Another participant clarifies that the normal force does not do work because it does not have a component in the direction of the displacement.
  • There is a discussion about the conditions under which forces do work, emphasizing that it depends on the force's component parallel to the displacement rather than force equilibrium.

Areas of Agreement / Disagreement

Participants generally agree that the speed at the finish line will be the same for both objects due to the net work being equal, but there is some uncertainty regarding the role of different forces and the conditions under which they do work. The discussion remains somewhat unresolved regarding the implications of these forces.

Contextual Notes

There are limitations in the discussion regarding the assumptions about forces acting on the objects and the specific conditions of the ramp setup. The participants do not fully resolve the implications of the normal force and its contribution to the net work.

Lori
I have the problem below.

I know that net work is equal to the change in kinetic energy which is Wnet= 0.5mv^2-0.5mvi^2.I also know that the work by force of gravity is the same for both objects. I don't understand why the objects would be the same speed at the finish line.
20171029_144753.jpg
 

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The speed will be the same. This does not mean that they will reach the finish line at the same time, block B has to travel longer.
 
Orodruin said:
The speed will be the same. This does not mean that they will reach the finish line at the same time, block B has to travel longer.
Can you explain why this would be the case? Would it be because net work is the same for both objects? Because if that's the case, then KE has to be the same and so the final velocities are the same.

However. I wouldn't know why new work is the same for both objects.
 
Lori said:
Would it be because net work is the same for both objects? Because if that's the case, then KE has to be the same and so the final velocities are the same.
Yes.

Lori said:
I wouldn't know why new work is the same for both objects.
You said it yourself in the first post:
Lori said:
I also know that the work by force of gravity is the same for both objects.
 
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Orodruin said:
Yes.You said it yourself in the first post:
Ahh yeah. I wasn't sure if force of gravity was the only work done on object but it makes sense since the ramp is frictionless and gravity is the only force applied.
 
Lori said:
Ahh yeah. I wasn't sure if force of gravity was the only work done on object but it makes sense since the ramp is frictionless and gravity is the only force applied.
Gravity is not the only force. There is also a normal force from the ramp. Can you figure out why it does no work?
 
Orodruin said:
Gravity is not the only force. There is also a normal force from the ramp. Can you figure out why it does no work?
Oh . Well the component in the y direction of gravity balances out normal force. So the normal force doesn't do any work.
 
Lori said:
Oh . Well the component in the y direction of gravity balances out normal force. So the normal force doesn't do any work.
It is not really a matter of force equilibrium. Whether a force does work or not depends on the force's component parallel to the displacement.
 
Orodruin said:
It is not really a matter of force equilibrium. Whether a force does work or not depends on the force's component parallel to the displacement.
Oh right! I was talking about net work. So the work that normal force does is 0
 

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