- #1

mibaokula

- 63

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hey guys, I'm new to this forum so i don't know if this has been already asked before

i saw this equation on special relativity explaining why objects with mass cannot travel at the speed of light

E = mc^2/(1-(v^2/c^2))^0.5

( hard to write on a computer. view the attachment for the equation or link here: http://upload.wikimedia.org/math/2/4/0/24090a520815f2d76b2be996acc6c9e2.png)

this makes sense right; if an object travels at the speed of light, the denominator becomes 0 and if the object has mass (say for example one arbitrary unit) you get a large number divided by zero - in other words an undefined energy to make this happen - impossible

but what confuses me it that if you take a photon which can travel at c, you still get an undefined energy. my question is: how are photons able to travel at c in a vacuum? do they carry undefined amounts of energy? or does the equation not work for light?

thanks

i saw this equation on special relativity explaining why objects with mass cannot travel at the speed of light

E = mc^2/(1-(v^2/c^2))^0.5

( hard to write on a computer. view the attachment for the equation or link here: http://upload.wikimedia.org/math/2/4/0/24090a520815f2d76b2be996acc6c9e2.png)

this makes sense right; if an object travels at the speed of light, the denominator becomes 0 and if the object has mass (say for example one arbitrary unit) you get a large number divided by zero - in other words an undefined energy to make this happen - impossible

but what confuses me it that if you take a photon which can travel at c, you still get an undefined energy. my question is: how are photons able to travel at c in a vacuum? do they carry undefined amounts of energy? or does the equation not work for light?

thanks