Why Can't I Solve This Static Friction Ladder Problem?

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SUMMARY

The discussion centers on solving a static friction problem involving a ladder, where the coefficient of friction (μ) is expected to be 0.18. The user presented their free body diagram (FBD) and equations of equilibrium, including force and moment equations. Despite multiple attempts to substitute values and solve for μ, the user consistently fails to achieve the expected result. A critical observation was made regarding the angles in the FBD, indicating they should be adjusted to 90 degrees minus theta.

PREREQUISITES
  • Understanding of static friction and the coefficient of friction (μ)
  • Knowledge of free body diagrams (FBD) in physics
  • Familiarity with equilibrium equations: ƩFx, ƩFy, ƩMA, and ƩMB
  • Basic trigonometry, specifically arctangent calculations
NEXT STEPS
  • Review static friction problems involving ladders and inclined planes
  • Practice drawing and analyzing free body diagrams (FBD) for various scenarios
  • Study the derivation and application of equilibrium equations in physics
  • Explore the relationship between angles and forces in static equilibrium
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and static equilibrium, as well as educators looking for examples of friction problems involving ladders.

jordan35
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Homework Statement


See attachment.


Homework Equations


F = μN

The Attempt at a Solution


I attached the FBD I drew. I then did
ƩFx = FA + FBcosθ - NBsinθ = 0
ƩFy = NA -W + NBcosθ + FBsinθ = 0
ƩMA = 19.5NB - 3.75W = 0
ƩMB = 3.75W - 7.5NA + 18FA = 0
FA = μNA
FB = μNB
θ = arctan(18/7.5) = 67.38°

I know μ is supposed to equal .18, but I can't get it. I've tried substituting different things I don't know how many times now, and I can usually get to an expression of just μ or μ and θ, but I can never get it to equal .18.
 

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The angles at the wall are wrong on your FBD. They should both be 90-theta.
 

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