- #1
shintashi
- 117
- 1
Over the past year, I've evaluated my own research and observations and matched them up with some statements from a pair of friends. One worked on a nuclear sub, and the other worked on an aircraft carrier. Both worked in the nuclear engine rooms.
As I've been refining the concept of thermodynamics, at least for my own research, I made this statement.
"
If hot is defined as the trend towards plasma, and plasma is a trend towards aetheric fire (nuclear fission) and both have a byproduct of radiation emission, then we must assume the following:
That cold is the absorbtion of radiation.
That cold is the reduction of electron orbits, which may create a condensation
If we follow this idea in aetheric physics, we may be bound to say that as the frequency of an electron merges with a lower frequency photon (higher energy/acceleration) then its acceleration would reduce on a quantum level, and the density of the electron would increase – it would become smaller. This would tell us that its frequency has increased, and its orbit has gotten smaller. If this is maintained further, the electrons would ultimately be in near contact with the nucleus of the atom. Although the original mass of the electron is very low, as it increases by 10 octaves, it would create, literally, a greater nucleus, proportional to the original electron count. And what of the nucleus, already 1000 times more dense than the electron, multiplied by its atomic mass (number of protons and neutrons) ?
If we can express an atom, such as gold, we have the following:
Au: Gold
Atomic Number 79
Atomic Weight ~197
Number of Protons: 79
Number of Electrons: 79
Number of Neutrons: 118
Mass of electron 9.1e-31 kg
Mass of proton 1.6e-27 kg
Mass of neutron ~1.6e-27 kg
1:1,758
Now assuming the octaval jump of gold transitioned into super densities, the first 10 octaves would yield a new atomic weight of around 276, a substance far more dense and radioactive at normal temperatures than ununoctium (element 118) It would have an atomic number of around 158.
More bizzarely, would be if the re-averaging “cold” effect were to also effect the nucleus, as while between the 10th and 11th octave the object’s electrons would resemble antiprotons, possibly seeking to merge and explode with the protons and creating an almost acidic effect dislodging the neutrons (creating a neutron radiation or explosion) the actual protons themselves could shift into some kind of Uber quark, a giant vortex, which itself, would technically occupy less space, with a greater magnetic field and a greater gravitational pull. The nuclear core, if following the principles of subatomic density- aetheric wave relationships, would reach 2e26 frequency each, with a “net aetheric disturbance” of 4.11e28...
(what then followed was a long list of octaval differences between frequency and mass)
... I do not know if it will be accepted, however, the basic notation is that at between 10 and 11 octaves, a dense substance, such as gold, uranium, etc, can be made to create an aetheric fusion explosion with the side effect of large amounts of neutron radiation. (a cold fusion reaction, with a neutron bomb side effect, several times more powerful than other reactions previously experienced)
"
ok, if you didn't notice, my main statement on any kind of "cold fusion" would depend on specifically targetting the electron fields, without altering the nucleus. Otherwise, you would slowly but surely turn the atom in question, into a black hole. (not for several octaves of increased frequency, but that would be the ultimate end result)
Because of the nature of this research, I do not believe "0 kelvin" is a proper function of measurement, nor that absolute zero exists. Objects do not "freeze", they have atomic condensation.
Also, very cold objects will release less random quantum particles, and less radiation of all categories. However, if you some how succeed in reducing the electrical field radius while increasing the field density, it will merge with the nucleus in a very bad way. It will transform the electrons into antirpotons, but the antiprotons will be in the same orbit as the nucleus, causing an antimatter explosion. I don't know what exactly will happen to the neutrons, but I assume that they might be "damaged" a bit releasing neutrinos, and if they remain intact, will create huge spray of neutrons flying out during the explosion.
Cold fusion, in otherwords, is a neutron-antimatter bomb, which is highly unlikely to work. What's worse, is that it will NEVER be a power source.
How does a nuclear reactor work ?
As my physics professor used to say, and my military firends further illustrated
its a big water heater, that spits out hot steam to turn turbines. The heater,
is a giant liquid battery using the electrochemical reactions between rods and a sort of electroconductive goup, - like what those energy drinks pretend to be. Its not much more impressive than a car battery, and no real "nuclear fusion or fission" cold or hot, is taking place. The only thing that is hot is the rods, which boil water. Yay.
How does a giant bomb turn into a water heater ? it doesnt. Plutonium and Uranium are just elements. Cold fusion won't ever work for anything except some rediculous NASA thrust experiment (since NASA specializes in using giant bombs for propulsion)
- Shin
As I've been refining the concept of thermodynamics, at least for my own research, I made this statement.
"
If hot is defined as the trend towards plasma, and plasma is a trend towards aetheric fire (nuclear fission) and both have a byproduct of radiation emission, then we must assume the following:
That cold is the absorbtion of radiation.
That cold is the reduction of electron orbits, which may create a condensation
If we follow this idea in aetheric physics, we may be bound to say that as the frequency of an electron merges with a lower frequency photon (higher energy/acceleration) then its acceleration would reduce on a quantum level, and the density of the electron would increase – it would become smaller. This would tell us that its frequency has increased, and its orbit has gotten smaller. If this is maintained further, the electrons would ultimately be in near contact with the nucleus of the atom. Although the original mass of the electron is very low, as it increases by 10 octaves, it would create, literally, a greater nucleus, proportional to the original electron count. And what of the nucleus, already 1000 times more dense than the electron, multiplied by its atomic mass (number of protons and neutrons) ?
If we can express an atom, such as gold, we have the following:
Au: Gold
Atomic Number 79
Atomic Weight ~197
Number of Protons: 79
Number of Electrons: 79
Number of Neutrons: 118
Mass of electron 9.1e-31 kg
Mass of proton 1.6e-27 kg
Mass of neutron ~1.6e-27 kg
1:1,758
Now assuming the octaval jump of gold transitioned into super densities, the first 10 octaves would yield a new atomic weight of around 276, a substance far more dense and radioactive at normal temperatures than ununoctium (element 118) It would have an atomic number of around 158.
More bizzarely, would be if the re-averaging “cold” effect were to also effect the nucleus, as while between the 10th and 11th octave the object’s electrons would resemble antiprotons, possibly seeking to merge and explode with the protons and creating an almost acidic effect dislodging the neutrons (creating a neutron radiation or explosion) the actual protons themselves could shift into some kind of Uber quark, a giant vortex, which itself, would technically occupy less space, with a greater magnetic field and a greater gravitational pull. The nuclear core, if following the principles of subatomic density- aetheric wave relationships, would reach 2e26 frequency each, with a “net aetheric disturbance” of 4.11e28...
(what then followed was a long list of octaval differences between frequency and mass)
... I do not know if it will be accepted, however, the basic notation is that at between 10 and 11 octaves, a dense substance, such as gold, uranium, etc, can be made to create an aetheric fusion explosion with the side effect of large amounts of neutron radiation. (a cold fusion reaction, with a neutron bomb side effect, several times more powerful than other reactions previously experienced)
"
ok, if you didn't notice, my main statement on any kind of "cold fusion" would depend on specifically targetting the electron fields, without altering the nucleus. Otherwise, you would slowly but surely turn the atom in question, into a black hole. (not for several octaves of increased frequency, but that would be the ultimate end result)
Because of the nature of this research, I do not believe "0 kelvin" is a proper function of measurement, nor that absolute zero exists. Objects do not "freeze", they have atomic condensation.
Also, very cold objects will release less random quantum particles, and less radiation of all categories. However, if you some how succeed in reducing the electrical field radius while increasing the field density, it will merge with the nucleus in a very bad way. It will transform the electrons into antirpotons, but the antiprotons will be in the same orbit as the nucleus, causing an antimatter explosion. I don't know what exactly will happen to the neutrons, but I assume that they might be "damaged" a bit releasing neutrinos, and if they remain intact, will create huge spray of neutrons flying out during the explosion.
Cold fusion, in otherwords, is a neutron-antimatter bomb, which is highly unlikely to work. What's worse, is that it will NEVER be a power source.
How does a nuclear reactor work ?
As my physics professor used to say, and my military firends further illustrated
its a big water heater, that spits out hot steam to turn turbines. The heater,
is a giant liquid battery using the electrochemical reactions between rods and a sort of electroconductive goup, - like what those energy drinks pretend to be. Its not much more impressive than a car battery, and no real "nuclear fusion or fission" cold or hot, is taking place. The only thing that is hot is the rods, which boil water. Yay.
How does a giant bomb turn into a water heater ? it doesnt. Plutonium and Uranium are just elements. Cold fusion won't ever work for anything except some rediculous NASA thrust experiment (since NASA specializes in using giant bombs for propulsion)
- Shin