MHB Why do these conditions have to be satisfied?

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The discussion focuses on the process of finding solutions to the congruence equation x^2 ≡ a modulo p^n, particularly when transitioning from a known solution modulo p to finding a solution modulo p^2. It highlights that if a solution exists modulo p, it can be used to find a corresponding solution modulo p^n for n > 1. The conversation emphasizes the importance of ensuring that the new solution x_1 satisfies both the original equation and the condition x_1 ≡ x_0 modulo p. Additionally, it notes that while the existence of a solution modulo p guarantees a solution modulo p^n, the reverse is not necessarily true, as demonstrated by counterexamples. Understanding these relationships is crucial for solving congruences in number theory.
evinda
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Hello! (Smile)

When we have a congruence $x^2 \equiv a \pmod {p^n}, n=1,2,3, \dots$ , and we know a solution $\pmod {p^n}$, then we also know a solution $\pmod {p^l}, l<n$.

For example, we know that for $n=3$, the congruence $\displaystyle{ x^2 \equiv 2 \pmod { 7^3}}$ has the solution

$$x_0 \equiv 108 \pmod {7^3} \equiv 108 \pmod {343}$$

Obviously, $x_0' \equiv 108 \pmod {49}$ is a solution of $x^2 \equiv 2 \pmod {7^2}$.

Also, $\displaystyle{ x_0'' \equiv 3 \pmod 7}$ is a solution of $x^2 \equiv 2 \pmod 7$.We want to do the reverse.

We know a solution $x_0 \pmod p$ of $x^2 \equiv a \pmod p$, and we want to find a solution $\pmod {p^2}$.
Applying this at the example $x^2 \equiv 2 \pmod 7$, we have $x_0=a_0=3$.

We are looking for a $x_1 \in \mathbb{Z}$, such that:

$$x_1^2 \equiv 2 \pmod {7^2} \text{ such that } x_1 \equiv x_0 \pmod{7}$$I haven't understood why, when we have a solution $\pmod p$, and we are looking for a solution $\pmod {p^2}$, we are looking for a $x_1$, such that:

$$x_1^2 \equiv 2 \pmod {7^2} \text{ such that } x_1 \equiv x_0 \pmod{7}$$

Could you explain it to me? (Sweating)
 
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I presume you are quoting a part of some book you have? You should snapshot the relevant page to give the readers a better idea of what is going on there (of course, only if you have a soft copy of it). From what I can exert from there, the relevant paragraph is merely a step of the whole calculations, which you have apparently omitted.

evinda said:
I haven't understood why, when we have a solution (mod p), and we are looking for a solution (mod p^2), we are looking for a x_1, such that:

Given a solution $x = x_0$ to $x^2 = a$ modulo some prime $p$, if you are looking for solutions of $x^2 = a$ modulo $p^2$, the first step would be to "sieve out" the natural numbers to look only for solutions $a \pmod{p}$ as

$$x^2 = a \pmod{p^2} \Longrightarrow x = a \pmod{p}$$

The converse doesn't hold, however! There is a lot of examples of numbers which differ modulo 2 and 4, for example. That is why I believe there is more to it than what you have posted.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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