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Homework Statement
Explain why a capacitor will discharge, although very slowly when there is high internal resistance?
Homework Equations
V=IR Q=V/C
The Attempt at a Solution
I am confused slightly by internal resistnace. Does that refer to regular resistance. From that high internal resistance results in large resistance therefore large p.d. therefore from Q=V/C V=QC so large voltage means that there will be large capacitance?