Why does a DC motor have a restricted speed?

Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
40 replies · 6K views
leafy said:
Unload motor require current to overcome friction. Loaded motor require current for the load. We assumed ideal, no friction, so the only requirement is current for the load.
Even without friction there are still electromagnetic losses, but OK let’s imagine all of that is somehow recaptured. So now you have a motor that you rev up and then just let it spin. If there is no current through it then it does nothing but spin. What is the point of having it there?
 
Physics news on Phys.org
Dale said:
Even without friction there are still electromagnetic losses, but OK let’s imagine all of that is somehow recaptured. So now you have a motor that you rev up and then just let it spin. If there is no current through it then it does nothing but spin. What is the point of having it there?
But there is current through it. Each time the switch close, current flow to speed up the wheel. Each time current flow to the 24V, curren flow slow down the wheel. Each cycle, there is a speed up and slow down. The net is zero current with is steady state.
 
I know that you think, or want, this problem to be about motors. But, you are missing some fundamental understanding about energy storage and transfer with magnetics. I strongly suggest you set aside the motor part and study a boost converter. It is the simplest circuit configuration that does this sort of thing. Understand the voltage and current waveforms in this simpler case first. Then move on to a DC motor, if you want.
 
I think solid state is harder.
 
leafy said:
But there is current through it.
If there is current through the motor then the current through the output is not equal to the current through the input. Also, if you are switching back and forth there is no reason that the “forth” current would equal the “back” current.
 
leafy said:
Hm... you might have read the diode wrong.
Well that's a bit of egg on my face then. That's what I get for not brushing up on my EE101. My apologies.
 
leafy said:
Unload motor require current to overcome friction. Loaded motor require current for the load. We assumed ideal, no friction, so the only requirement is current for the load.
The portion of rotation that charges the batteries will put a mechanical load on the motor, slowing it down. The battery will need to supply current after this to speed it back up. You have created a (bad) motor generator, which is not new as has been discussed.
It is much more difficult than you imagine to create new stuff
Linus Pauling was once asked how he had so many good ideas. He said "I just have a lot of ideas and I get rid of the bad ones" One needs to be able to do both of these efficiently to be successful. With respect, you need some more work on the second part.

/
 
  • Like
Likes   Reactions: Dale
leafy said:
But there is current through it. Each time the switch close, current flow to speed up the wheel. Each time current flow to the 24V, curren flow slow down the wheel. Each cycle, there is a speed up and slow down. The net is zero current with is steady state.
Thread is closed temporarily for Moderation...
 
leafy said:
Each time the switch close, current flow to speed up the wheel. Each time current flow to the 24V, curren flow slow down the wheel. Each cycle, there is a speed up and slow down. The net is zero current with is steady state.
I believe that by “net is zero current” you mean that the current speeding up the motor with the 12 V supply is the same as the current slowing down the motor with the 24 V recharging. That is simply false, there is nothing that would require it from a circuits standpoint and, as you noticed, the conservation of energy forbids it.

As perpetual motion machines are not permitted to be discussed here, this thread will remain closed.
 
  • Like
Likes   Reactions: sysprog