acen_gr
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Mentallic said:Did you just do what I think you did?
To quote myself from earlier:
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Oopps. My bad.
Mentallic said:Did you just do what I think you did?
To quote myself from earlier:
![]()
acen_gr said:Oopps. My bad.But I will work on it again. I'm sure my answer would still be the same. I'm going to repost it to make it clear :shy:
acen_gr said:0 = -1
^ [STRIKE]again[/STRIKE], makes no sense![]()
Mentallic said:No way! 2x=0 implies that x=0. Of course this makes sense!
Such things that would be nonsense would be if we divided by 0, or if we tried to take the square root of a negative, or the arcsin of a value outside the range -pi/2 to pi/2, or something like 1=0.
Mentallic said:Fixed. There was never a first time that you proved that it makes no sense hehe
acen_gr said:I'm sure my answer would still be the same.
acen_gr said:Since my proof that time is senseless (because I did the wrong way of taking cosine of both sides), this x = 0 doesn't happen to be a solution right? Because what I was trying to prove is that solution is nowhere to find.
Mentallic said:Say I want to find the solution to x such that it satisfies x+2=0, so I go about it by dividing through by 2 (incorrectly) and get x+1=0, so x=-1. Is x=-1 a solution to x+2=0?
Since you made an error in your calculations, of course the answer isn't going to correct
Mentallic said:Haha just don't let me catch you taking the cosine of a sum in the wrong way again![]()
acen_gr said:(1) The post is not misstated.
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(c) is the odd one out isn't it?
the given range for x is fine for the 1st two but not for (c)
"arcsin" is misspelled as arccsin.
what other carelessness is there?
ask your teacher for a model answer - showing working.
I used gnu-octave to plot the graph ... the solution would have been the intersection of the curve with the line y=90.UPDATE: Anyway sir, how do you find out the solution of trigonometric equations through graphs? Like the one you posted in post #27.
The code was:
> x=0:0.0125:1;
... says to make a vector whose first entry is 0, incrementing by 1/80 until it reaches 1;
> y=acos(x)-asin(1-x);
... this is the function I want to plot a graph of: y will be in radiens;
... the result of y will be a vector the same size as x, each entry being the result of plugging the corresponding x entry into the equation.
> plot(x,y*(180/pi))
... this plots the graph - I scales the y-axis to give degrees.
... plot(X,Y) treats the two vectors X and Y as ordered pairs (Xi, Yi).
I could have plotted a line at y=90 by doing:
> plot([0,1],[90,90])
... because the plot function automatically draws a line between data points.
... plot will interpret the two vectors as the points (0,90) and (1,90).
generally: if I want to solve f(x)=c, then I could plot y=f(x) and y=c, plot both on the same axis and note the intersection ... reading x off the horizontal axis.
That is usually good for simple relations or for an approximation. For more precision, I'd use Newton-Raphson on f(x)-c=0 - using the graph to select initial values of x.
Some ability to plot the relations you are trying to solve is invaluable: it tells you what kind of solution you are aiming for. Octave is free/libre as well as free/gratis, others use Matlab or Mathematica. Only masochists use spreadsheets for stuff like this.
I guess that is pretty much all this topic exhausted - cheers.
Simon Bridge said:(1) The post is not misstated.
![]()
(c) is the odd one out isn't it?
the given range for x is fine for the 1st two but not for (c)
"arcsin" is misspelled as arccsin.
what other carelessness is there?
ask your teacher for a model answer - showing working.