Why Does cos(180-Θ) = -cos(Θ)?

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The discussion explains why cos(180-Θ) equals -cos(Θ) using the unit circle concept. It highlights that cosine represents the x-coordinate of the terminal angle on the unit circle, and as the angle moves to 180 degrees, the x-values reflect across the y-axis. This reflection results in cos(180-Θ) being negative, as it falls in the second quadrant where cosine values are negative. The relationship is further supported by the cosine addition formulas and the ASTC rule, which indicates the sign of trigonometric functions in different quadrants. Understanding these principles clarifies the relationship between the angles and their cosine values.
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1. Explain, using a unit circle diagram, why cos(180-Θ) = -cos(Θ)

2. My Attempt at a Solution:
I have no idea how to begin thinking of this. I don't know any of the obvious details of the question, the only rational thought I can currently form is that cos(Θ) = the x-coordinate of the terminal angle's intersection with a unit circle, however, I don't even know if that's related to the question. I cannot form any simple thoughts regarding this question. I have no idea where to begin, so I'm just wondering if someone here might be able to say something that could point me in the correct direction of an answer. Thanks!
 
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Draw a circle... Think about how you can indicate cosine on the circle. You already know the definition of cosine, so you are on the right track...
 
Or if you have had the addition formulas you can use the formula for ##\cos(a-b)##.
 
LCKurtz said:
Or if you have had the addition formulas you can use the formula for ##\cos(a-b)##.

The question asked to explain using a unit circle diagram.
 
If you look at the unit circle, you can notice that the x-values are "reflective" of each other in the top half. This is because at the 90\deg point, x=0 so when you decrease the angle, x increases the same amount as it would decrease if you had rather increased the angle. From this observation, you can make the statements that \cos(90-\theta)=x and \cos(90+\theta)=-x Now, do what you will with those statements and the relation \cos(a+b)=\cos(a)\cos(b)-\sin(a)\sin(b)
 
Here's an image I made (sorry for the bad quality) that will show you the intuition behind that formula:
ywwru.png

$$\color{#50F}{\cos(\pi-\theta)}=-\color{fuchsia}{\cos(\theta)}.$$
 
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"unit circle" means its radius is 1. So sine = opp/hyp = opp/1 = opp
 
What you have to remember is that when you draw your unit circle, you need to remember ASTC.

The region which 180-θ falls in is the second quadrant — or, the S quadrant. In this quadrant, only sin is positive. So cos(180-θ)=-cosθ

Hope this helps ~| FilupSmith |~
 
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