Why does E=MC² use the speed of light squared as a constant?

  • Thread starter Thread starter nazarbaz
  • Start date Start date
  • Tags Tags
    Work
nazarbaz
Messages
22
Reaction score
0
I understand that energy depends on mass but why multiply it by C² and not some other constant ?
Several subquestions pops up from the previous one : how Einstein ended up with this equation ? Why a fundamental limit of nature as C should be squared (what does a squared limit mean) ? Is it related to some deep truth about the nature of matter and energy ? Is it a "model dependent" mathematical trick ? What is a constant of nature ?
 
Physics news on Phys.org
We get a question like this every other day (or more), you can just do a search and I'm sure you'll see a lot of threads with the answers in them.
 
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...

Similar threads

Replies
2
Views
1K
Replies
124
Views
16K
Replies
13
Views
3K
Replies
6
Views
2K
Replies
11
Views
2K
Back
Top