Why Does Fundamental Freq Have Largest Amplitude?

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The fundamental frequency typically has the largest amplitude due to the shape of the vibrating medium, often resulting in a maximum at the fundamental mode in a Fourier Transform. However, it is possible for higher harmonics to dominate, especially with asymmetrical plucking or specific damping techniques. The amplitude of lower frequency harmonics is generally greater because of the relationship between stiffness and mass in vibrating objects, where lower stiffness allows for larger displacements. Standing waves are formed through the superposition of two waves traveling in opposite directions, with their relative phases varying along the medium, leading to points of constructive and destructive interference. This understanding clarifies the apparent contradiction between wave superposition and the existence of standing waves.
Jimmy87
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Please could somebody explain why the fundamental frequency always has the biggest amplitude in comparison to the rest of the harmonics?
 
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The reason that the fundamental usually dominates will be because of the shape of the string when plucked - the Fourier Transform of the initial shape will normally have a maximum at the fundamental mode. But it doesn't necessarily. You can excite a string with asymmetrical plucking at 1/4 and 3/4 along its length and get the first overtone dominating with no significant fundamental OR by placing a dampening finger, half way along a guitar string (or other places) you can get higher overtones (not exact harmonics unless the medium is ideal - but referred to by guitarists as harmonics - but they're not Physicists so it's OK for them)
 
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The fundamental doesn't always have the biggest amplitude.

For example see Fig 2 (page 6 of the PDF) in http://www.haskins.yale.edu/sr/SR111/sr111_23.pdf

Several counter-examples of organ reed pipes here: http://www.pykett.org.uk/reedpipetones.htm - e.g Fig 9 the 5th harmonic is loudest, followed by the 3rd.

The reason why lower frequency harmonics usually have bigger amplitudes than higher, is because of the basic equation for the frequency of a vibrating object, ##f = (1/2\pi)\sqrt{K/M}## where K and M measure the stiffness and mass of whatever is vibrating. Often, the amount of vibrating mass is about the same for all the harmonics, and the stiffness increases as the frequency increases. For a fixed amount of forrce, you get a bigger amplitude of vibration from a low stiffness (because displacement = stiffness / force), and so the low frequency harmonics tend to have bigger amplitudes.
 
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Don't they die out??

Two waves traveling in opposite direction should die out according to super position principle (Zero amplitude). Then how standing waves are produced? Is this not a contradiction? Please help. thank you.
 
pscience said:
Two waves traveling in opposite direction should die out according to super position principle (Zero amplitude). Then how standing waves are produced? Is this not a contradiction? Please help. thank you.

The anti- phase condition only occurs right at the termination. The relative phases of incident and reflected wave vary with distance and superposition produces the standing wave.
 
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Hello! Let's say I have a cavity resonant at 10 GHz with a Q factor of 1000. Given the Lorentzian shape of the cavity, I can also drive the cavity at, say 100 MHz. Of course the response will be very very weak, but non-zero given that the Loretzian shape never really reaches zero. I am trying to understand how are the magnetic and electric field distributions of the field at 100 MHz relative to the ones at 10 GHz? In particular, if inside the cavity I have some structure, such as 2 plates...
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