Why does gravity dictate min.velocity for centripetal force?

AI Thread Summary
The discussion centers on the relationship between centripetal force and gravity in the context of swinging a yo-yo in a vertical circle. It explains that at the minimum velocity, the centripetal force required to keep the yo-yo in motion must equal the gravitational force acting on it. If the speed is too low, the string cannot exert enough upward force to maintain the yo-yo's circular path, leading to a failure to complete the motion. The key point is that gravity provides the necessary force to keep the yo-yo moving at the top of its swing, but it is not the source of centripetal force itself. Understanding this distinction is crucial for solving related physics problems.
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Homework Statement


You are playing with a yo-yo with a mass of 225 g. The full length
of the string is 1.2 m. You decide to see how slowly you can swing
it in a vertical circle while keeping the string fully extended, even
when the yo-yo is at the top of its swing.
(a) Calculate the minimum speed at which you can swing the yo-yo
while keeping it on a circular path.

Homework Equations


Fg = mg
Fc = v^2/r

The Attempt at a Solution


All I want to know is why is it that the "centripetal force has to be exactly equal to the force of gravity" when the object will be at its smallest possible velocity (aka minimum velocity)?

Why is it that gravity is supplying the centripetal force needed for the object to maintain in circular motion at the least possible velocity?
 
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Gravity is not supplying the centripetal force (perhaps that term is causing your problem). The centrifugal force must at least equal gravity or your yo-yo will not make it over the top.
 
Another way to look at it:

Solve for the force the string needs to exert on the yo-yo to make it swing in in a vertical circle. Then realize that at the top of the circle, if the speed is too small, then the string needs to push up on the yo-yo. But unless you have a stiff string, it can't push.
 
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