Why Does Griffiths Use Two Directions of Light in His Length Contraction Proof?

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maxverywell
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In Griffiths book (Intro to Electrodynamics, page 489) he uses one simple gedanken experiment with train, lamp and mirror, to prove the length contraction [tex]\Delta x'=\gamma \Delta x[/tex]. My question is why he uses two directions of light and not just only one?
For example, when we use, for observer in the train, [tex]\Delta t'=\frac{\Delta x'}{c}[/tex] instead of [tex]\Delta t'=2\frac{\Delta x'}{c}[/tex] and for observer in the ground [tex]\Delta t=\frac{\Delta x}{c-u}[/tex] instead of [tex]\Delta t=\frac{\Delta x}{c-u}+\frac{\Delta x}{c+u}[/tex], it gives us incorrect result. Why is this happening?
 
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No one can explain this?

Let's suppose that the light is moving in direction in which the train is moving. So, for observer in the train:

[tex]\Delta t'=\frac{\Delta x'}{c}[/tex] (1)

and for observer in the ground:

[tex]\Delta t=\frac{\Delta x}{c-u}[/tex] (2)

Applying the time dilation formula [tex]\Delta t'=\frac{\Delta t}{\gamma}[/tex] to (1) and (2) we find that:

[tex]\Delta x=\frac{\gamma(c-u)\Delta x'}{c}[/tex]
 
maxverywell said:
Applying the time dilation formula [tex]\Delta t'=\frac{\Delta t}{\gamma}[/tex] to (1) and (2) we find that:

[tex]\Delta x=\frac{\gamma(c-u)\Delta x'}{c}[/tex]
Realize that the time dilation formula applies to time measurements recorded on a single moving clock. You can't apply it to the one-way travel time, since multiple clocks on the moving train are involved--those clocks are not in synch (according to the track frame). If you use the round trip time, which is measured on a single clock, then you can apply the time dilation formula.
 
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