Why Does J(-n)(x) Obey the Parity Rule?

asdf1 · 2005-12-26T11:39:57+00:00

why does J(-n) (x)=[(-1)^n]Jn(x)?

Thread 'Direction Fields and Isoclines'

I sketched the isoclines for $$ m=-1,0,1,2 $$. Since both $$ \frac{dy}{dx} $$ and $$ D_{y} \frac{dy}{dx} $$ are continuous on the square region R defined by $$ -4\leq x \leq 4, -4 \leq y \leq 4 $$ the existence and uniqueness theorem guarantees that if we pick a point in the interior that lies on an isocline there will be a unique differentiable function (solution) passing through that point. I understand that a solution exists but I unsure how to actually sketch it. For example, consider a...

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Thread 'Direction Fields and Isoclines'

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