Why Does Metal Require More Energy for Electron Emission?

AI Thread Summary
Metal requires more energy for electron emission compared to hydrogen atom excitation due to the differences in energy binding. For metals, the photon energy must meet or exceed the work function to release an electron, with any excess energy translating into the electron's kinetic energy. In contrast, for hydrogen atoms, the photon energy must precisely match the energy difference between quantized levels for excitation, as the electron remains bound to the atom. This distinction arises because empty space does not possess discrete energy levels like those found in atoms. Ultimately, the mechanisms of electron emission from metals and excitation in hydrogen are fundamentally different due to their unique energy requirements.
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Homework Statement


in my book , i was told that for the emission of electron from a metal surface to occur , the photon which incident on the metal must have at least the energy more than the work function of metal , whereas for the emission of electron from H atom, the photon must have exactly the same energy between the energy levels... is there reason for this ?

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The Attempt at a Solution

 
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The statement about H atoms is incorrect.
 
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Simon Bridge said:
The statement about H atoms is incorrect.
please refer to the underlined notes.
 

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The notes in the pic talk about the excitation of hydrogen by absorption of an electron.
In post #1 you wrote:
...whereas for the emission of electron from H atom, the photon must...
emission and excitation are different things.
the equivalent to the work function for hydrogen is the ionization energy - 13.6eV
 
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Simon Bridge said:
The notes in the pic talk about the excitation of hydrogen by absorption of an electron.
In post #1 you wrote:

emission and excitation are different things.
the equivalent to the work function for hydrogen is the ionization energy - 13.6eV
sorry. noted my mistake.
now , my question is for excitation for hydrogen atoms , why must the photon energy hf exactly equal to difference between energy level , whereas for emission of electron for metal surface , the incident photon energy can be equal or MORE than the work function of metal?
 
You are still comparing apples and pears - but I think I can see what you are getting at.
Recap:

When you excite an atom, the electron is still bound to the atom.
If you excite a metal, the electron is still bound to the metal.
In both cases, the incoming energy must be exactly a transition energy between two levels.

For a photon to knock an electron off a metal, it must have energy at least equal to the work function.
If the energy is more than the work function - the difference is the kinetic energy of the electron.
If the energy is exactly the work function, then the electron barely breaks out and it's 50:50 that it will go back in.

For a photon to knock an electron off an atom, it must have energy at least equal to the atom's ionization energy.
If the energy is more than the ionization energy - the difference is the kinetic energy of the electron.
Basically the same as for the metal.

I'm thinking: you may be asking why empty space does not have discrete energy levels like inside an atom - is that the case?
But you may also be asking why you cannot eject an electron from a metal by giving it energy exactly equal to the work function.
Or it may be something else.
 
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