Why does my wave equation appear to move backwards?

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Homework Help Overview

The discussion revolves around a wave equation in the standard form (y=sin(kx-wt) and its behavior when graphed. The original poster expresses confusion about the wave appearing to move backwards despite having a positive constant velocity.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants explore the nature of wave directionality and question the implications of the wave equation's phase component. There is a discussion about the possibility of reflection and the conditions under which waves can appear to move in reverse.

Discussion Status

Some participants have offered insights regarding wave direction and reflection, while the original poster has acknowledged a misunderstanding related to the phase component of the wave equation. The conversation reflects a mix of interpretations and clarifications without reaching a definitive consensus.

Contextual Notes

The original poster notes that the wave appears to move backwards even with small time values, raising questions about the assumptions made regarding the wave's behavior and the coordinate system used.

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I have a wave eqn that is of the standard form (y=sin(kx-wt)) and have a positive constant velocity. But when I graph it, it appears to be moving backwards with a greater t producing a lesser x for each specific y. How can this be?

The eqn is y=10sin(18.35x-6283t)
 
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It could be a reflected wave.

The wave direction is either + or - with respect to the coordinate system. In one dimension, waves can move in one of two directions - forwards or backwards.
 
How can it be a reflected wave when there is nothing to reflect it with? The time I subed in was tiny and it still showed a backward moving wave. So the wave is going backwards immediately after t=0.
 
I know where I made my mistake. I didn't fully understand how the phase component worked. The wave turns our to be a forward traveling wave after all.
 

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