You can make the ##\phi## component of current = 0 by the way you wind the wire.Adesh said:But in spite of all these I can't seem to understand how the current have no ##\phi## component. Well, in that toroid we have current going on in circles and really I don't anything more than this.
Please help me!
Yes, I got it thanks. You know my main problem was that I was unable to decompose a circle (that is the loop of a wire wound around the toroid) into just ##\hat{r}## and ##\hat{z}## components, because you know when we draw a circle in ##xy## plane we decompose it’s line elements into ##\hat{r}## and ##\hat{\phi}## directions (if we use polar coordinates) . So, it was hard for me to imagine such a situation where we had no ##\phi## component.rude man said:You can make the ##\phi## component of current = 0 by the way you wind the wire.
If you use just one winding then obviously there must be a ##\phi## component of current since each turn of wire is connected to the next by a short run of ##\phi## section to get around the toroid's periphery.
But if you do 2 windings (layers) the second winding's sections' current can cancel out the first if properly wound.
Right. The trick is two windings with the second nulling the ##\phi ## component from the first.Adesh said:Yes, I got it thanks. You know my main problem was that I was unable to decompose a circle (that is the loop of a wire wound around the toroid) into just ##\hat{r}## and ##\hat{z}## components, because you know when we draw a circle in ##xy## plane we decompose it’s line elements into ##\hat{r}## and ##\hat{\phi}## directions (if we use polar coordinates) . So, it was hard for me to imagine such a situation where we had no ##\phi## component.