Dec 4, 2011 #1 clava345 Messages 3 Reaction score 0 I'm a little bit rusty with my differential equations, and can't seem to see how solving for 1/r d/dr (r dT/dr)=0 has the solution T(r)=C_1*ln(r)+C_2
I'm a little bit rusty with my differential equations, and can't seem to see how solving for 1/r d/dr (r dT/dr)=0 has the solution T(r)=C_1*ln(r)+C_2
Dec 4, 2011 #2 JJacquelin Messages 801 Reaction score 35 integration of d/dr (r dT/dr)=0 leads to (r dT/dr) = C1 dT = C1 dr/r integration of dT=C1 dr/r leads to t = C1 ln(r) + C2
integration of d/dr (r dT/dr)=0 leads to (r dT/dr) = C1 dT = C1 dr/r integration of dT=C1 dr/r leads to t = C1 ln(r) + C2