Why does the PIV in centre tap rectifier is twice of the V source?

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SUMMARY

The discussion centers on the peak inverse voltage (PIV) in a full-wave center tap rectifier, specifically why the PIV requirement for the diode is twice the input voltage from the transformer. Participants clarify that in a center-tapped transformer, when one winding produces a voltage of +V, the other produces -V, resulting in a total PIV of 2V across the diode. The grounding of the center tap does not affect the voltage across the diode; rather, it is the vector subtraction of the voltages at each end of the transformer winding that determines the PIV. Understanding the relationship between the transformer windings and the diode's operation is crucial for accurate circuit analysis.

PREREQUISITES
  • Understanding of full-wave rectification
  • Knowledge of transformer operation and center tap configurations
  • Familiarity with diode characteristics and peak inverse voltage (PIV)
  • Basic circuit analysis skills, including voltage referencing
NEXT STEPS
  • Study the operation of full-wave center tap rectifiers in detail
  • Learn about transformer phasing and its impact on voltage outputs
  • Explore the concept of peak inverse voltage (PIV) in various rectifier configurations
  • Examine practical applications of center tap transformers in power supply design
USEFUL FOR

Electrical engineers, students studying power electronics, and anyone involved in designing or analyzing rectifier circuits will benefit from this discussion.

  • #61
NascentOxygen said:
They are all correct, except for the last one. The error is tiny & trivial, but it should be
PIV = 2Vp(sec) - 0.7 V

Yes. Kirchoff 2 applies here. How anyone could imagine that a diode actually supplies emf escapes me.

All of this can be resolved by properly specifying the (multiple) output voltages of the centre tapped transformer.
 

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