Why Does the Restoring Force Use k1x + k2x in Spring Oscillations?

Click For Summary
SUMMARY

The discussion centers on the calculation of the restoring force in a system with two springs characterized by spring constants k1 and k2. The confusion arises from the assertion that the overall restoring force is k1x + k2x, despite initial reasoning suggesting it should be k1x - k2x. The explanation clarifies that one spring's increased tension and the other spring's decreased tension combine to yield a net restoring force of k1x + k2x, where k equals the sum of the individual spring constants. This is crucial for understanding spring dynamics in oscillatory motion.

PREREQUISITES
  • Understanding of Hooke's Law and linear spring behavior
  • Familiarity with equilibrium positions in mechanical systems
  • Knowledge of spring constants and their role in restoring forces
  • Basic concepts of tension in springs and forces acting on masses
NEXT STEPS
  • Study the derivation of the restoring force in multi-spring systems
  • Explore the implications of spring constants in oscillatory motion
  • Learn about the dynamics of coupled oscillators
  • Investigate the role of tension in mechanical systems and its distinction from spring force
USEFUL FOR

Physics students, mechanical engineers, and anyone studying oscillatory systems and spring dynamics will benefit from this discussion.

jsmith613
Messages
609
Reaction score
0
attachment.php?attachmentid=142547&d=1334684647.png

Looking at the three diagrams we can see that there are three possible situations

(a) mass is to the right of eqm
(b) mass is at eqm
(c) mass is to the left of eqm
(eqm = equilibrium)

Lets look at position (a)

If we consider the tension in both springs:
the tension in the spring on the left has increased by k1x
the tension in the spring on the right has decreased by k2x

So the overall restoring force SHOULD BE k1x - k2x
(the spring on the left is trying to pull it back to the left and the spring on the right is trying to pull it the right hence the forces act in opposite directions)

BUT according to my book the overall restoring force is k1x + k2x...how?

Any help is greatly appreciated

exact quote:
Book
Consider the mass at some point during motion. Let its displacement from eqm be x at that point. One of the two springs has been extended by x and the other has been shortened by x. So compared with eqm one spring has extra tension k1x and the other string has its tension reduced by k2x.
The spring constants for the individual springs are k1 and k2.
The extra tension from one spring combines with the reduced tension from the other to give a restoring force of k1x + k2x.
The restoring force can be written as: F = -kx
where k = k1 + k2
The - sign indicates it acts towards eqm
 
Physics news on Phys.org
The compressed spring is not pulling away from the eqm but pushing towards. IE it is under compression.
 
Integral said:
The compressed spring is not pulling away from the eqm but pushing towards. IE it is under compression.

oh right
thanks
 
Integral said:
The compressed spring is not pulling away from the eqm but pushing towards. IE it is under compression.

why is tension not present here?
(I don't understand the explanation given)?
 

Attachments

  • Tension.png
    Tension.png
    20.6 KB · Views: 603
jsmith613 said:
why is tension not present here?
(I don't understand the explanation given)?
I don't understand the choices. There are two forces acting on the hanging mass: gravity and the force from the spring. Of course, a stretched spring exerts a tension. So I don't know the intention of having 'tension' vs 'spring' as separate choices: you could call that force the spring force or the tension force exerted by the spring.

And the given explanation reads like gibberish. Where is this question from?
 
Integral said:
The compressed spring is not pulling away from the eqm but pushing towards. IE it is under compression.

Even if both springs are under tension all of the time, the restoring force would still be k_1x + k_2x. There's an increased force to the left, because the left spring pulls harder and a decreased force to the right because the right sprint pulls less hard than in the equilibrium position. This will give the same effect as an increased force to the right.
 
A linear spring pulled from equilibrium exerts a force k*x. A linear spring compressed from equilibrium exerts a force k*x. Thus, the force is k*x+k*x.

I'm not sure where the issue lays
 
By the way, that attached .png is garbage, no offence.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 20 ·
Replies
20
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K