Why doesn't Newtons third law also apply to the frame?

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The discussion revolves around the application of Newton's third law in the context of a locomotive colliding with a wall. It is established that the force exerted by the locomotive on the wall is equal in magnitude to the force exerted by the wall on the locomotive, supporting answer (b). However, confusion arises regarding the interaction between the wall and its frame, as the wall breaks upon impact. Participants clarify that the forces between the train and the wall differ from those between the wall and the frame, which can lead to different outcomes. Ultimately, the conversation emphasizes that while Newton's third law holds true, the complexity of interactions in a collision can complicate the understanding of force distribution.
Callista
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Homework Statement


A locomotive has broken through the wall of a train station. During the collision, what can be said about the force exerted by the locomotive on the wall?
a)The force exerted by the locomotive on the wall was less than the force exerted by the wall on the locomotive.
b) The force exerted by the locomotive on the wall was the same in magnitude as the force exerted by the wall on the locomotive.
c) The force exerted by the locomotive on the wall was larger than the force the wall could exert on the locomotive.
d) The wall cannot be said to "exert" a force; after all, it broke.

Homework Equations


NA?

The Attempt at a Solution


I understand that the answer must be b, due to Newton's 3rd law. However, what I don't understand is my textbooks explanation for why the wall gives out.

"Answer (b). Newton’s 3rd law describes all objects, breaking or whole. The force that the locomotive exerted on the wall is the same as that exerted by the wall on the locomotive. The framing around the wall could not exert so strong a force on the section of the wall that broke out."

According to Newtons 3rd law there must be an equal and opposite reaction between the wall and the train. So why isn't there a equal and opposite reaction between the wall and the frame? I feel like there must be an unequal force somewhere to cause the wall to break, but I can't understand how this could be possible according to Newtons 3rd law.
 
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The opposing forces on the train are the force from the wall frame (delivered via the wall), the force required to break the wall into pieces, the force required to accelerate the wall pieces, plus some heat in the form of speeding up the molecules in the wall pieces. The more you dig into where the forces go the more complicated it is. For example what about the force required to move the air that results in the sound of the crash, etc. So, everyone can't help but simplify the description to just say the force was in the wall.
There is an equal and opposite force exchange in the wall - frame interface, but it didn't include all of the forces applied by the train. Some of those forces did other things.
 
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Callista said:
According to Newtons 3rd law there must be an equal and opposite reaction between the wall and the train. So why isn't there a equal and opposite reaction between the wall and the frame?
There is.

I feel like there must be an unequal force somewhere to cause the wall to break, but I can't understand how this could be possible according to Newtons 3rd law.
The mistake in your reasoning is assuming that the force exerted by the train on the wall is equal in magnitude to the force exerted by the frame on the wall. Those are two different interactions, so Newton's third law says nothing about how they compare.
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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