Line said:
Can someone give me a down to Earth explanation why this works?
first, Line, do you understand that "light" is the propagation of electromagnetic (E&M) fields or "waves" and the physics that describes that propagation (called "Maxwell's Equations"). are you at that level? if not, i don't know quite where to begin with a down to Earth explanation.
i would not call the constancy of
c (for all frames of reference) an axiom for which there is no idea why such principle exists (and we just notice it experimentally). it's because we can detect no intrinsic difference between different
inertial frames of reference (two observers moving at constant velocities relative to each other both have equal claim to being "stationary", there is no good reason to say that one is absolutely stationary and the other is the one that is moving) and that the laws of physics, namely Maxwell's equations, apply to both frames of reference equally. if two different observers, neither accelerated and moving relatively to each other, are examing the very same beam of light (an electromagnetic wave), for both observers, when they apply and solve Maxwell's equations for the propagation of the EM wave, they both get the same speed of
c out of solving Maxwell's eqs.
so we
do have a good idea for why the speed of propagation of E&M is the same for all inertial observers that may or may not be moving relative to each other. it's because, we cannot tell the difference between a "moving" vacuum and "stationary" vacuum, that there
is no difference between a moving and stationary vacuum and then there is not apparent reason for the observed speed of light to be different.
this is different than for sound. the physics of Maxwell's Equations make no reference to a medium that conducts the electromagnetic field (and, indeed, the Michaelson-Morley experiement failed to show that such a hypothetical medium, called
"aether" exists - if it
does exist, it seems to be moving around in the same frame of reference as the Earth going around the sun because no matter what time of day or season of the year, no one could detect with the M-M apparatus any motion through this aether). but for sound, the physics describe it as compressions and rarefractions of the air (or whatever other matter medium). there is no such thing as sound in a vacuum (but there is light). so if you feel the wind moving past your face from left to right (say at a speed of 20 m/s), you will also measure the speed of sound from a source on your left to be 20 m/s faster than sound from a source in front of you and 40 m/s faster than a sound that is at your right. now you can repeat that setup and get an identical result if there is no wind but
you are moving (toward your left) through the air at a speed of 20 m/s. so the observer that is stationary (relative to the air) will look at a sound wave and measure it at something like 334 m/s, but
you, moving through the air toward the source at 20 m/s will measure the speed of that very same sound wave to be 354 m/s.
now think of the same thing, but instead you two observers are out in some vacuum of space somewhere and are looking at the same beam of light. the other observer is holding the flashlight and measuring the speed of light to be 299792458 m/s.
you are moving toward that observer at a speed of, say, 1000 m/s and looking at the very same beam of light that the other observer is. you are thinking that you would measure it at a speed of 299793458 m/s, right? but
why should it be any different for you? you have equal claim to being stationary (and it's the guy with the flashlight is moving toward you at 1000 m/s). you cannot feel the vacuum moving past you at a speed of 1000 m/s, in fact there is no physical meaning to the vacuum moving past your face at 1000 m/s like it's a wind. you cannot tell the difference between you moving and the other guy as stationary or if the roles were reversed and there is no meaning to any notion of who is stationary
absolutely and who is moving.
so then, if there is no meaningful difference, if
both of you have
equal claim to being stationary (and it's the other guy that is moving), then the laws of physics (particularly Maxwell's Equations) have to be exactly the same for both of you, both in a qualitative sense, and in a quantitative sense. both of you have the same permittivity of free space (\epsilon_0) and permealbility of free space (\mu_0). so when you apply Maxwell's equations to this E&M wave (of this flashlight beam), you will see that this changing
E field is causing a changing
B field which, in turn, is causing a changing
E field which is causing a changing
B field, etc. now for both of you, the laws (Maxwell's Eqs. and the parameters \epsilon_0 and \mu_0) are the same. now, it turns out, when we solved Maxwell's Equations for this case, we get a propagating wave and the wave speed is
c = \sqrt{\frac{1}{\epsilon_0 \mu_0}} [/itex]<br />
<br />
<b>but that's the same for both you and the other observer!</b> (even though you are both moving relative to the other.) there is no reason that the other guy should solve the Maxwell's equations and get a different c than you get (because you have the same \epsilon_0 and \mu_0)! even if you two are looking at the very same beam of light. this is as far down to Earth as i can put it. does it do it for you, Line?