Why doesn't stereographical projection map to the origin from the north pole?

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Homework Help Overview

The discussion revolves around the properties of stereographic projection, particularly focusing on why points from the north pole do not map to the origin of the plane. The subject area includes concepts from geometry and topology, specifically relating to the mapping of the unit sphere to the plane.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the mapping of points from the north pole to the plane and question the implications of the projection formula. There is discussion about the relationship between points on the sphere and their corresponding points in the plane, particularly regarding the origin and the concept of the "point at infinity."

Discussion Status

Some participants express confusion initially but later indicate a clearer understanding of the projection process. There are multiple interpretations being explored regarding the mapping of points and the geometry involved.

Contextual Notes

Participants are considering the implications of using a unit sphere and the definitions of points in relation to the projection, including the nature of the equator and the radius of the sphere.

pivoxa15
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I noticed that it doesn't project to the origin of the plane from the north pole. However the projection describes it as mapping to the whole equitorial plane which is wrong!

i.e take S^1 projecting to R.

From the north pole the projection formula is y=-(x-a)/a however a can't be 0. So the origin is never mapped.
 
Last edited:
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Stereographic projection maps the plane to the unit sphere thus: Let the equator of the sphere be the unit circle in the plane. Call the north pole of the sphere N. The map any point P in the plane to the point Q on the sphere by constructing the ray [tex]\vec{NP}[/tex] and assigning the point Q to be the point of intersection of the sphere and the ray.
Clearly the origin of the plane is mapped to the south pole of the sphere, points inside the unit circle in the plane are mapped to the southern hemisphere of the sphere, and points outside the unit circle in plane are mapped to the northern hemisphere of the sphere. The so-called "point at infinity" is mapped to the north pole.
 
benorin said:
Stereographic projection maps the plane to the unit sphere thus: Let the equator of the sphere be the unit circle in the plane. Call the north pole of the sphere N. The map any point P in the plane to the point Q on the sphere by constructing the ray [tex]\vec{NP}[/tex] and assigning the point Q to be the point of intersection of the sphere and the ray.
Clearly the origin of the plane is mapped to the south pole of the sphere, points inside the unit circle in the plane are mapped to the southern hemisphere of the sphere, and points outside the unit circle in plane are mapped to the northern hemisphere of the sphere. The so-called "point at infinity" is mapped to the north pole.

Whew! This was a *clear* response. I thought this was how it worked, but after reading the question I became confused.

The line through the north pole that will "go to infinity" will be tangent to the top of the sphere and parallel to the plane, as soon as you incline it, even slightly, it will go through the north pole and through one other point on the sphere.

But if the equator the sphere is the unit circle on the plane isn't the radius of the sphere going to be less than one?

If it's a unit sphere the unit circle would be mapped like this:

http://en.wikipedia.org/wiki/Image:Stereoprojnegone.svg

Right?
 
Last edited:
I see what is going on now. It all works.
 

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