Why dont integrate all electric fields in a sphere?

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SUMMARY

The discussion centers on the application of Gauss's Law in determining electric fields within a sphere with a volumetric charge distribution exhibiting spherical symmetry. The electric field is defined as E=3AB*r*e^(-1.5Br^2). It is established that integrating the electric fields from 0 to R is unnecessary because the resultant electric field inside the sphere is zero, confirming the effectiveness of using only the external field for calculations.

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axcelenator
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If volumetric charge distribution has spherical symmetry
I want to find the trapped charge a in certain radius
Why did not need to do an integral from 0 to R to all the electric fields inside the sphere but take only the external field(how gauss law says)?

The Electric fiels is: E=3AB*r*e^(-1.5Br^2)
 
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You could do that, it's just that the result for the field inside the radius is zero.
 

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