Why don't neutral atoms distort the electric field?

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Discussion Overview

The discussion revolves around the behavior of electric fields in the presence of neutral atoms within a positively charged conductor that contains a cavity. Participants explore the implications of Gauss's law and the role of atomic structure in electrostatics, particularly in the context of electrostatic equilibrium.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant describes a system with a positive charge inside a cavity of a positively charged conductor, concluding that the electric field inside the conductor is zero due to Gauss's law.
  • Another participant questions whether the Gaussian surface enclosing the positive charge would yield a non-zero electric flux, suggesting that the presence of neutral atoms should affect the electric field.
  • It is proposed that neutral atoms can be treated as shells of charge, with the electric field from these atoms being negligible at distances greater than approximately 10^-10 m.
  • Some participants emphasize that in classical electrostatics, it is practical to consider only protons and electrons, while noting that atoms can also become polarized and carry magnetic fields, complicating the analysis.
  • There is a mention that the small effects of individual atoms tend to average out when considering large numbers of atoms over long distances.

Areas of Agreement / Disagreement

Participants express differing views on the influence of neutral atoms on the electric field, with some asserting that their effects are negligible while others suggest that they should be considered. The discussion remains unresolved regarding the extent to which neutral atoms impact the electric field in this context.

Contextual Notes

Participants acknowledge that classical electrostatics simplifies the behavior of charges and does not fully account for atomic polarization or the complexities introduced by magnetic fields. The discussion highlights limitations in the assumptions made about the uniformity of charge distribution and the effects of individual atomic structures.

davidbenari
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Suppose I have a positively charged conductor with a cavity. There's a positive charge inside the cavity and the system has reached electrostatic equilibrium. Then there's negative charge surrounding the cavity and positive charge on the surface of my conductor. If I apply gauss law to the interior of the conductor I conclude that the electric field is zero at every point of my gaussian surface, and if it weren't so, then charged particles would be accelerating or whatever.

But my question is: why don't the atoms in the interior affect the electric field? I mean, even if the atoms are neutral (consider now a non-conducting material) they have charges inside that should somehow alter the electric field in the neighborhood.

What's going on?

Thanks.
 
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davidbenari said:
Suppose I have a positively charged conductor with a cavity. There's a positive charge inside the cavity and the system has reached electrostatic equilibrium. Then there's negative charge surrounding the cavity and positive charge on the surface of my conductor. If I apply gauss law to the interior of the conductor I conclude that the electric field is zero at every point of my gaussian surface, and if it weren't so, then charged particles would be accelerating or whatever.
... didn't you say there was a positive charge inside the cavity?
If your gaussian surface enclosed the positive charge, then wouldn't the flux through the surface be non-zero?

But my question is: why don't the atoms in the interior affect the electric field? I mean, even if the atoms are neutral (consider now a non-conducting material) they have charges inside that should somehow alter the electric field in the neighborhood.
Quite right - the electric field from "neutral" atoms is not exactly zero everywhere. That is an approximation, which holds very well at distances greater than around 10-10m.

Try this: treat a neutral atom as a shell of negative charge surrounding an equal positive charge ... place a gaussian surface around the entire thing and work out the field.

However
 
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If there is a positive charge inside my cavity, and the system has reached electrostatic equilibrium, then there is also negative charge surrounding the interior surface of the cavity so as to make the electric field inside the conductor zero by gauss's law.
 
http://www.physics.sjsu.edu/becker/physics51/images/23_20ConductingTube.JPG

Like (c)
 
Last edited by a moderator:
I'm starting to think that it's more practical to assume that the only things that exist are swarming protons and electrons for these problems. Is this the idea in classical electrostatics?
 
If there is a positive charge inside my cavity, and the system has reached electrostatic equilibrium, then there is also negative charge surrounding the interior surface of the cavity so as to make the electric field inside the conductor zero by gauss's law.
...
Like (c)
In the diagram you showed me, the brown area is a solid conductor - there is no field inside the conductor.
The white area in the middle is a cavity - there is certainly an electric field inside the cavity.
The diagram is not quite accurate - diagram (c) should have more "+" signs on the outer surface than the others.
But I think I'm clear on what you are talking about now.

Classical electrostatics treats charges as infinitely divisible fluids.
This gets modified slightly when you realize that, for normal solids, the mobile fluid is the negatively charged one - but for most purposes it does not matter.

Electrons and protons belong to the particle model of charge - they are not the only charged particles, so just talk about positive and negative charge unless otherwise specified.

IRL: atoms can become polarized as well as charged, and they carry magnetic as well as electric fields, thisall makes things tricky ... as you advance in your education you will learn how to handle these things in more detail. Meantime you'll notice that the electrostatics you are doing involves quite long distances and very large numbers of atoms so the small effects of individual atoms will tend to average out.
 

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