Why Don't Neutron-Neutron States Exist?

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SUMMARY

Neutron-neutron (NN) and proton-proton (PP) states do not exist due to the spin-dependent nature of the nucleon-nucleon force, which favors parallel spins. In fermionic systems like NN and PP, spins must be anti-parallel, preventing the formation of bound states. The only stable bound state involving neutrons is found in neutron stars, where gravitational forces counteract repulsive forces. First-order approximations using quantum chromodynamics (QCD) and Yukawa potentials can demonstrate the absence of bound states for NN systems.

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Mr T
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Hey all,

My year 13 physics students stumped me with this one: Why don't Neutron-Neutron (or P-P for that matter) states exist?

Thanks in anticipation...

Mr T
 
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It would be really nice to have a first principles calculation showing this, but I'm fairly sure such a thing does not exist.

The textbook argument is this: the nucleon-nucleon force is spin dependent; specifically, parallel spins are favoured. If you had a proton-proton or neutron-neutron system, then due to them being fermions, the spins would have to be anti-parallel. Deuterium can be spin-parallel, and the nucleon-nucleon force is only just enough to hold it together (for instance, no excited bound state of it exists).
 
For NN you could just look at the potentials holding it to gether vs pushing it apart.
I think you can do some first order approximations for QCD (say, a heavy and light meson exchange yukawa potential) + gravity (very very weak) + spin+etc.

I think you can show that there should be no bound states. The reason I mention gravity is that there IS a bound state for a neutron particle, its called a neutron star. Gravity is finally large enough at that level to pull in the same amount that the repulsive forces (degeneracy pressure+temp) are pushing out.
 

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