Why electrons move up if the Magnetic field is Horizontal?

Click For Summary
SUMMARY

The discussion centers on the behavior of electrons in a horizontal magnetic field, specifically addressing the Lorentz force. The key takeaway is that while the magnetic field is horizontal, the electrons experience a vertical force due to their velocity components. The Lorentz force equation, F = q (E + (v/c) × B), illustrates that only the vertical component of the electron's velocity contributes to the force when the motion is perpendicular to the electric field.

PREREQUISITES
  • Understanding of the Lorentz force equation
  • Familiarity with electric and magnetic fields
  • Basic knowledge of vector components in physics
  • Concept of charge and its interaction with fields
NEXT STEPS
  • Study the implications of the Lorentz force in different field orientations
  • Explore the relationship between electric fields and magnetic fields in particle motion
  • Investigate the role of velocity components in electromagnetic interactions
  • Learn about applications of the Lorentz force in particle accelerators
USEFUL FOR

Physics students, educators, and professionals in electromagnetism, particularly those interested in the dynamics of charged particles in electric and magnetic fields.

mo0nfang
Messages
13
Reaction score
0
<--Why electrons move up if the Magnetic field is Horizontal?

at 0:14 <-- the Magnetic field is Horizontal but the electrons are also moving horizontally...
 
Physics news on Phys.org
The force is perpendicular to the motion and perpendicular to the electric field, with its strength proportional to the sine of the angle between the two directions.
In the first video the motion is vertical, therefore there is a horizontal force.
In the second video the direction of motion changes, but the horizontal component is along the electric field - it does not lead to a force. Only the vertical component of the velocity leads to a force.
 
I guess you mean magnetic field? The Lorentz force on a point particle is
$$\vec{F}=q \left (\vec{E}+\frac{\vec{v}}{c} \times \vec{B} \right).$$
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 1 ·
Replies
1
Views
936
  • · Replies 23 ·
Replies
23
Views
5K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 42 ·
2
Replies
42
Views
4K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K