scope
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hi,
could you tell me why traveling faster than light is impossible?
thank you!
could you tell me why traveling faster than light is impossible?
thank you!
Dickfore said:It turns out, as well, that the speed of propagation of electromagnetic fields in vacuum is equal to this limiting speed. As light is an electromagnetic wave, this limiting speed is most commonly referred to as the speed of light in vacuum.
scope said:ok, thank you then I am still worried with the spin of the electron. i know that it is widely believed that an electron is a point particle and its spin has not really the classical meaning.
but IF we suppose that its spin is really its proper angular momentum and IF we suppose that's its radius is very small but not 0, then I know that in classical physics, L=mvr leads to v>c.
but let's suppose the same conditions but let's do the calculation in special relativity. the electron is not moving at relativistic speed relativitely to us (at rest), and let's then suppose that gamma is 1 in the direction of its motion
then L=r.p and r is classical, and p=mv.
then I do believe that m is the same as the rest mass, and therefore the calculation in special relativity leads also to v>c.
is that calculation mathematically correct? i am just asking if that is mathematically correct?.
the problem is that its mass m is not a relativistic mass , it is a rest mass, so i wonder if the calculation in classical mechanics leads to the same result as in special relativity, mathematically?
ghwellsjr said:Our mechanism to "push" is essentially light itself and if it has a speed limit then we won't be able to use it to "push" something faster than it, itself, can go.
It's not just that it's "widely believed" that its spin is nonclassical. It's mathematically impossible for a spin of \hbar/2 to result from motion of a particle through space. You can only get integer multiples of \hbar that way.scope said:ok, thank you then I am still worried with the spin of the electron. i know that it is widely believed that an electron is a point particle and its spin has not really the classical meaning.
but IF we suppose that its spin is really its proper angular momentum and IF we suppose that's its radius is very small but not 0, then I know that in classical physics, L=mvr leads to v>c.
jambaugh said:Your formula assumes all the mass is at the same radius which implies a ring or cylinder shape...but that's just a matter of a multiplicative form factor. W.r.t whether the relativistic and non-relativistic calculations agree, they do. If we imagine an electron as a little spinning ring of mass then the mass we measure for the electron is the relativistic mass given the velocity of the rotation and that also is the mass one uses in the relativistic angular momentum via L=m v r = m omega r^2.
But let's try it this way. Take a loop of mass m and spin it to some fixed angular momentum. Then measure its tangential velocity v and total ("relativistic") mass M. The mass M will be rest mass times the relativistic factor and the angular momentum will be fixed L = M v r. Now shrink r and you will see the loop speed up. Note this takes some energy because you are increasing the total energy and so the relativistic mass will increase:
L = M v r = M' v' r'. You will find as you try to spin it past v=c by reducing r that you again hit that M->infinity business.
Note another aspect of the electron. There is energy tied up in the surrounding electromagnetic field. This contributes to the observed mass. If you try to concentrate the finite charge to small enough radius you will again get infinite energy and thus infinite mass.
What it more there is also an angular momentum component possible for that surrounding electromagnetic field.
You can from a classical perspective think of the electron as nothing except a charge monopole whose mass comes wholly from the EM field surrounding it, and avoid the infinite mass for a point charge by assuming a masking effect of the vacuum (the vacuum polarizes so as to spread the charge around.)
This goes to show that it is not correct to think of an electron as a point mass/charge except relative to a larger scale.
bcrowell said:By this logic, a rocket wouldn't be able to accelerate to a speed greater than its own exhaust velocity. Hand-waving arguments like this don't prove anything.
That is not correct, nor is it implied by bcrowell's correct statement.ghwellsjr said:What if I said, by your logic, a rocket could exceed the velocity of light?
I can't see how that would work.There are many ways that velocities greater than c can appear in relativity without violating any of the above considerations. For example, one can point a laser at the moon and sweep it across, so that the spot moves at a speed greater than c,