Why Graphing Tools doesn't represent hole in a graph

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Graphing tools often fail to represent holes in functions, which occur at points where the function is undefined. For instance, the function x/(√(x-1)-1) should theoretically show a hole, but many graphing applications do not indicate this clearly. Point discontinuities, like those in the function (x^2-5x+6)/(x-2), may not be visually marked unless specifically requested, as they are often too small to notice. Graphing software typically prioritizes showing continuity in the surrounding area, but users can access coordinates to confirm whether a point is defined. Overall, while graphing tools can depict discontinuities, they often do not highlight them prominently.
22990atinesh
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Why Graphing Tools doesn't represent hole in a graph of a function. A Hole at a point in a graph is point where function is not defined.Suppose there is a function

##\frac{x}{\root{x-1}-1}##

Its should be like this
Capture.jpg


But online tools and even my android graphing tool app shows graph like this
Capture_2.jpg


What I'm saying is that, apart from circle there must be some sort of marks representing that the function is not defined here.
 
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What's your function? Plotting ## \frac{x}{\sqrt{x-1}-1} ## gives me a different graph.

Anyhow, point discontinuities aren't always shown on generated graphics, but you can force the tool to do it.

For example, take the function ## \frac{x^2-5x+6}{x-2} ## which has a point discontinuity at ##x=2##.

Using WolframAlpha:

>> plot (x^2-5x+6)/(x-2)gives this:
MSP10311g15fe9bg4f36dc700000f418id2faei64h0.gif


>>plot discontinuities of (x^2-5x+6)/(x-2) gives this:
MSP42992072699fi0ig0dci000031436gf7gf8gd36b.gif


Now, as for why these graphic tools don't show where point-discontinuities are? I don't know, I guess you have to ask for it, because we usually don't need to see it shown that big. Theoretically, the exact point ##x=2## in our example is so small if it were to be shown it would be unnoticeable. Note that the function behaves at ##x=1.9999999...## exactly how it does right after ##x=2##. The circle of point-discontinuity is just a symbol showing that something is going on here; it's not a real hole because point-discontinuties are actually impossible to show.
 
Last edited:
About online graphing websites [for example Desmos]:
I think that because the program is trying to show that the function is continuous on a very close interval beside the point where the function has a discontinuity, but if you click on that point it will give you its coordinate and whether it is defined or not.
Untitled23.png
 
22990atinesh said:
Why Graphing Tools doesn't represent hole in a graph of a function. A Hole at a point in a graph is point where function is not defined.Suppose there is a function

##\frac{x}{\root{x-1}-1}##

Its should be like this
Capture.jpg


But online tools and even my android graphing tool app shows graph like this
Capture_2.jpg


What I'm saying is that, apart from circle there must be some sort of marks representing that the function is not defined here.

Sorry mistyped the function ##\frac{x}{\root{x+1}-1}##
 
22990atinesh said:
Sorry mistyped the function ##\frac{x}{\root{x+1}-1}##
\root{} doesn't mean anything in LaTeX. Use \sqrt{} for a square root and \sqrt[3]{} for a cube root and similar for higher-degree roots.

Your expression should be written as # #\frac{x}{\sqrt{x+1}-1}# # (without the spaces between the # characters). This renders as ##\frac{x}{\sqrt{x+1}-1}##
 
Mark44 said:
\root{} doesn't mean anything in LaTeX. Use \sqrt{} for a square root and \sqrt[3]{} for a cube root and similar for higher-degree roots.

Your expression should be written as # #\frac{x}{\sqrt{x+1}-1}# # (without the spaces between the # characters). This renders as ##\frac{x}{\sqrt{x+1}-1}##
Hmm Sorry little mistake
 

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