Why is Glass Opaque to IR and UV, But Not Visible Light?

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Discussion Overview

The discussion centers on the optical properties of glass, specifically why it is opaque to ultraviolet (UV) and infrared (IR) light while remaining transparent to visible light. Participants explore theoretical explanations, practical observations, and the implications of these properties in various contexts, including everyday experiences and applications in technology.

Discussion Character

  • Exploratory
  • Debate/contested
  • Technical explanation

Main Points Raised

  • Some participants propose that transparency is due to the energy levels of electrons in glass, which do not absorb visible light but do absorb UV light.
  • Others argue that while glass is generally opaque to UV and IR, it allows visible light to pass through, which can lead to heating effects in enclosed spaces like cars.
  • A participant questions the logic behind the heating of car interiors, suggesting that IR is trapped inside due to the glass's transparency to visible light.
  • Another participant challenges the claim that glass does not allow UV or IR to pass, citing the use of glass lenses in UV and IR cameras.
  • Some participants reference the work of Richard Feynman, discussing how photons interact with glass and may be re-emitted, though this interpretation is contested.
  • There are claims regarding the attenuation of UV light by glass, with some asserting that it is heavily attenuated compared to visible light.
  • Participants discuss the implications of glass's optical properties for pets and the need for UV filters, indicating a nuanced understanding of light transmission through glass.

Areas of Agreement / Disagreement

Participants express multiple competing views regarding the optical properties of glass, particularly concerning its interaction with UV and IR light. The discussion remains unresolved, with differing interpretations of how glass transmits and absorbs various wavelengths of light.

Contextual Notes

There are limitations in the discussion regarding assumptions about the definitions of transparency and opacity, as well as the specific conditions under which glass may or may not transmit certain wavelengths of light. The discussion also reflects varying levels of understanding about the physics of light-matter interactions.

peter.ell
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According to my understand of what makes something transparent, it's because a given wavelength of light doesn't have sufficient energy to raise the electrons in a material to a higher energy level, so the photons are not absorbed and continue on.

This explains why glass is transparent for visible light but absorbs UV, as UV has enough energy to excite the electrons to the allowed energy levels of silicon...but then why is glass also opaque to lower energy IR?

Thank you.
 
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Hm ... if glass is opaque to UV and IR, I wonder why it is that my car seat gets so damned HOT in the summer?
 
Don't solar cells (silicon) use mostly visible light? So there must be a fair amount of energy in the visible spectrum of sunlight.
 
phinds said:
Hm ... if glass is opaque to UV and IR, I wonder why it is that my car seat gets so damned HOT in the summer?

It's actually because glass is transparent to visible light, which is absorbed by the materials inside your car and then that light is re-radiated at a longer wavelength--IR. This IR is then trapped inside of the car because the glass windows keep it in.
 
peter.ell said:
It's actually because glass is transparent to visible light, which is absorbed by the materials inside your car and then that light is re-radiated at a longer wavelength--IR. This IR is then trapped inside of the car because the glass windows keep it in.

ahhh but the flaw in your logic is that the glass window let the IR in for a start

Glass doesn't stop UV or IR ... if it did IR or UV cameras would not work they ALL have glass lenses
the only time glass WONT pass either IR or UV is if it is specially treated to produce a filter to those wavelengths. for example I have a screw on UV filter on my digital SLR camera
I wouldn't need that if glass normally stopped UV

cheers
Dave
 
Last edited:
peter.ell said:
According to my understand of what makes something transparent, it's because a given wavelength of light doesn't have sufficient energy to raise the electrons in a material to a higher energy level, so the photons are not absorbed and continue on.

Thank you.

actually looking at the first part of your post, that isn't quite right. According to the late Prof. Richard Feynman, basically, photons entering the glass are absorbed by the atoms of the glass exciting electrons causing those electrons to emit new photons that carry on through the glass.
that is, I understood from his lectures, that the photons coming out the other side of the glass (or those that appear to be reflected out the same side) are not necessarily the same ones that went into the glass.

cheers
Dave
 
Last edited:
peter.ell said:
It's actually because glass is transparent to visible light, which is absorbed by the materials inside your car and then that light is re-radiated at a longer wavelength--IR. This IR is then trapped inside of the car because the glass windows keep it in.

Another flaw in your logic ... ;)

in a ventilated area, put your arm under a sheet of glass in summer sun, I bet it gets seriously sunburnt. The IR energy isn't getting trapped anywhere except in your skin! :)

Not sure where your got your understandings from, but unfortunately, you were seriously misled

cheers
Dave
 
davenn said:
ahhh but the flaw in your logic is that the glass window let the IR in for a start

He didn't say that it does. In fact, he states that it doesn't.

Glass doesn't stop UV or IR ... if it did IR or UV cameras would not work
Wrong.
 
davenn said:
put your arm under a sheet of glass in summer sun, I bet it gets seriously sunburnt. The IR energy isn't getting trapped anywhere except in your skin! :)

IR? Sunburn? Really?

Another flaw in your logic ... ;)

Not sure where your got your understandings of sunburn from, but unfortunately, you were seriously misled
 
  • #10
NascentOxygen said:
He didn't say that it does. In fact, he states that it doesn't.

yes he does read his original comments! he states IR and UV doesn't pass through glass


Wrong.

try again as I said if glass stopped UV then there would be no need for me to use UV filters!

I really don't know if you are just picking a fight/argument
or you really have no understanding of optics

I suspect the former and you are just wanting to be nasty
in which case I will leave you to your stupidity as I have no inclination of trying to deal with the likes of you any further
 
  • #11
wiki:
Ordinary glass is partially transparent to UVA but is opaque to shorter wavelengths, whereas silica or quartz glass, depending on quality, can be transparent even to vacuum UV wavelengths. Ordinary window glass passes about 90% of the light above 350 nm, but blocks over 90% of the light below 300 nm.
http://en.wikipedia.org/wiki/Ultraviolet
UV is from 10 to 400 nm, so no, you won't get a sunburn trough the glass.

Air warmed by the heat from hot interior surfaces is retained in the building by the roof and wall. In addition, the warmed structures and plants inside the greenhouse re-radiate some of their thermal energy in the infra-red, to which glass is partly opaque, so some of this energy is also trapped inside the glasshouse.
http://en.wikipedia.org/wiki/Greenhouse
 
  • #12
davenn said:
yes he does read his original comments! he states IR and UV doesn't pass through glass
That's what I said he said.

try again as I said if glass stopped UV then there would be no need for me to use UV filters!
If glass didn't heavily attenuate UV then there would be no need for vets to warn pet owners that sitting bird and reptile cages beside a window will not provide their pets with adequate daily UV light unless the the window is actually open.

I really don't know if you are just picking a fight/argument
or you really have no understanding of optics
Just gently correcting your misunderstanding, actually. I think where you're going wrong is with your perception of attenuation as an "all or nothing" thing. It isn't. While all frequencies of light are transmitted through ordinary glass, UV is more heavily attenuated than is visible light.

<rant elided>
 
  • #13
davenn said:
actually looking at the first part of your post, that isn't quite right. According to the late Prof. Richard Feynman, basically, photons entering the glass are absorbed by the atoms of the glass exciting electrons causing those electrons to emit new photons that carry on through the glass.
that is, I understood from his lectures, that the photons coming out the other side of the glass (or those that appear to be reflected out the same side) are not necessarily the same ones that went into the glass.

cheers
Dave

I don't think that can be quite right - at least not when it's put in that blunt way. If new photons were generated as a result of old ones being absorbed, the re-radiated em waves would be in all directions so no coherent image could be seen. ( You couldn't identify actual 'Rays' going through.) The only time that photons are generated in this, coherent, way is during Laser operation and that only happens when Stimulated Emission takes place.

It is true to say, however, that photons do react with the medium they pass through, though (the velocity of the wave slows down) so there is 'something' in what you say - it's not just that simple, I think.

Transmission of em through materials is different for all frequencies (energies). Gamma rays tend to get through any but the most dense metals fairly easily - they just hit the nuclei and may get absorbed. Low energy (RF) waves do not 'pass through' metals but generate currents by generally 'vibrating' all the free electrons in the metal (in a 'bulk' interaction - rather than a one photon / one electron interaction. This causes reflection plus some absorption.

For crystals and amorphous (covalent?) materials, (insulators, at least), there can be slight shifting (polarising) of the charges within molecules which may involve more or less loss / absorption, depending on the wavelength and the material. Perhaps this is somewhere near what you got from the Feynman lecture? He did love his Feynman Diagrams but he stressed that they are only meant to be a short hand version of what goes on and shouldn't be regarded as an rigorous description of a 'mechanism'.
 

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