Deepak K Kapur said:
@A. T.
you seem to say the opposite of what Janus said...
A.T. is talking about tidal forces, which so far have been neglected.
The effect of weightlessness as described in Janus' analogy depends on all elements of a body (cars) being pulled equally. That is to say, the gravitational field must be uniform - a force vector drawn from any point in the field acting on a test particle must have the same magnitude and direction.
This uniformity is approximately true far away from gravitational sources, but it is not exact. An extended object, such as e.g. a planet in orbit around a star, will experience a bit smaller force acting on its edge opposite the star than on its closer edge, and the direction towards the centre of the sun (the source of gravity) is a bit different when standing on the leading edge (or e.g. the north pole) and the trailing edge (or the south pole). Each of those differences causes a net force to emerge, stressing the body. This force is what causes tides, hence the name.
The more deviation from uniformity, the larger the effect.
However, this is not the same thing as been discussed in the question in the first post - the acceleration felt due to tidal force does not arise as a result of slowing down and accelerating in orbit.
If you could get a perfectly uniform field, and get it to change in a perfectly uniform fashion, then anybody accelerated in this field would not experience any stresses - these changes in motion could not be felt.