Why is it not possible to see the interference pattern of white light

5ymmetrica1
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'The colour seen when white light is used as a source for a Young’s double slit experiment are sometimes mistaken for the spectrum of visible light.'
Why is this not possible with a two slit interference pattern?

I know that the different wavelengths will all cause interference with each other, but is there a better explanation than this?
 
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5ymmetrica1 said:
'The colour seen when white light is used as a source for a Young’s double slit experiment are sometimes mistaken for the spectrum of visible light.'
Why is this not possible with a two slit interference pattern?

I know that the different wavelengths will all cause interference with each other, but is there a better explanation than this?

Because there are so many different wavelengths in white light that the interference pattern from each wavelength overlaps each other and washes out.

Zz.
 
Deleted following insulting reply.
 
Last edited:
technician said:
It is correct that white light consists of arrange of colours (wavelengths) but it is perfectly straightforward to produce 2slit interference pattern the fringes obtained are essentially white but 'blue' can be seen at the 'inner' edge of the fringes and 'red' can be seen at the outer edge. This is a standard demonstration at A level and details are given in A level textbooks.

That's sad, considering how easy and cheap it is nowadays to obtain a laser pointer with a good-enough monochromatic light source.

Zz.
 
ZapperZ said:
That's sad, considering how easy and cheap it is nowadays to obtain a laser pointer with a good-enough monochromatic light source.

Zz.

This is an insulting comment.. I have reported it and I have deleted my response.
 
Last edited:
technician said:
This is an insulting comment.. I have reported it and I have deleted my response.

Not sure what is "insulting" about that. You obviously read WAY differently than what I wrote.

The "sad" comment was directed at the situation, i.e. that one had to use a white light to demonstrate interference effects, rather than obtaining a simple, cheap, monochromatic light source. You appear to interpret it as being directed at your comment.

Zz.
 
5ymmetrica1 said:
'The colour seen when white light is used as a source for a Young’s double slit experiment are sometimes mistaken for the spectrum of visible light.'
Why is this not possible with a two slit interference pattern?

I know that the different wavelengths will all cause interference with each other, but is there a better explanation than this?

It is possible to see the pattern for white light with 2 slits...we did it at school using car head lamp bulbs.
 

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