Why is K an anti-unitary operator in (26)?

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SUMMARY

The discussion clarifies that the operator K in equation (26) is an anti-unitary operator, not a unitary operator. This distinction is crucial because K implements complex conjugation, which affects the transformation properties of operators U_T and U_C. The equation (U_T·K)·(U_C·K) = U_T·U_C* holds true due to this anti-unitary nature of K, which leads to the expected behavior of complex conjugation in quantum mechanics.

PREREQUISITES
  • Understanding of anti-unitary operators in quantum mechanics
  • Familiarity with unitary transformations and their properties
  • Knowledge of complex conjugation and its implications in quantum theory
  • Basic comprehension of quantum mechanics notation and terminology
NEXT STEPS
  • Study the properties of anti-unitary operators in quantum mechanics
  • Learn about the implications of complex conjugation in quantum transformations
  • Explore the role of unitary and anti-unitary operators in quantum mechanics
  • Review the specific applications of equation (26) in quantum theory as presented in the referenced paper
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Quantum physicists, students of quantum mechanics, and researchers interested in the mathematical foundations of quantum theory will benefit from this discussion.

thatboi
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Hey all,
I just wanted to double check my understanding of (26) in the following notes: https://arxiv.org/pdf/1512.08882.pdf.
Is the reason that ##(U_{T}\cdot K) \cdot (U_{C}\cdot K) = U_{T}\cdot U_{C}^{*}## because ##K## is a unitary operators and thus ##(K\cdot U_{C}\cdot K) = U_{C}^{*}## as we would expect of a unitary transformation?
 
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thatboi said:
Hey all,
I just wanted to double check my understanding of (26) in the following notes: https://arxiv.org/pdf/1512.08882.pdf.
Is the reason that ##(U_{T}\cdot K) \cdot (U_{C}\cdot K) = U_{T}\cdot U_{C}^{*}## because ##K## is a unitary operators and thus ##(K\cdot U_{C}\cdot K) = U_{C}^{*}## as we would expect of a unitary transformation?
No, it says explicitly that K is an anti-unitary operator, not a unitary one. Specifically, K implements complex conjugation.
 

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