Why is kinetic energy NOT proportional to degrees F/C

[babacanoosh]

Hello all,
I have a question, that regards a problem I was assigned. The problem is:

Why is kinetic energy NOT proportional to degrees F/C?

-I understand it has something to do with absolute zero Kelivn...not C. Thanks

Any help would be greatly appreciated...I need a response by tomorrow. Thanks again

 

[AbedeuS]

PV = \frac{1}{3}Nmv_{rms}^{2}
PV = nRT

Therefore:
\frac{1}{3}Nmv_{rms}^{2} = nRT

Rearranging:
v_{rms} = \sqrt{\frac{3nRT}{Nm}}

Since N = nN_{a} and R = kN_{a} it can be simplified to:

v_{rms} = \sqrt{\frac{3nN_{a}kT}{nN_{a}m}} = \sqrt{\frac{3kT}{m}}

Therefore:
v_{rms}\propto \sqrt{T}

EDIT: Similar looking results are found if you doing the same with Boltzmann curves or whatever else tickles your fancy.