Why Is My Algebra Proof Not Working?

  • Thread starter Thread starter EsponV
  • Start date Start date
  • Tags Tags
    Algebra Proof
Click For Summary

Homework Help Overview

The discussion revolves around a proof involving algebraic manipulation and mathematical induction. The original poster expresses difficulty in resolving an algebraic proof and seeks assistance in identifying errors in their reasoning.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the equivalence of expressions involving powers of 2, particularly questioning the transformation of 2*(2^n) and its implications in the proof. There is a focus on clarifying the correct application of algebraic identities.

Discussion Status

Some participants have provided insights into the algebraic expressions involved, noting potential misinterpretations. The original poster acknowledges an algebraic error, indicating a productive exchange of ideas, though no consensus on the proof's resolution has been reached.

Contextual Notes

The original poster references specific problems and their attempts, including uploaded images of the problem and their work, which may not be fully accessible to all participants. There is an emphasis on understanding the correct application of algebraic rules in the context of the proof.

EsponV
Messages
15
Reaction score
0
Greetings,

It's been awhile since I've done induction or proofs in general, but I could not figure out where I went wrong on this one for the life of me. If anyone has an idea it would be much appreciated. I've uploaded a picture of the problem in the book as well as of my work. I thought I did everything correct but the algebra isn't working out.

Thanks all.

Problem (12): http://imageshack.us/m/30/7931/20110512190557593.jpg

Attempted Solution: http://imageshack.us/m/812/3723/2011051222200544.jpg
 
Last edited:
Physics news on Phys.org
What is 2*(2^n) equal to? [Hint: not 2^(2n)]
 
Right, so isn't 2*(2^n) = 2^(n+1) ?

But then I end up with 2^(2n) = 2^(n+1) which eventually leads to n = 1, yes?
 
EsponV said:
Right, so isn't 2*(2^n) = 2^(n+1) ?

But then I end up with 2^(2n) = 2^(n+1) which eventually leads to n = 1, yes?

I don't understand how you could end up with 2^{2n}=2^{n+1} again. If you apply the correct formula in the line

(2^n-1)+2^{(n+1)-1}=2^{n+1}-1

then surely you'd end up with something else??
 
Ah, I had been incorrectly stating that 2^n + 2^n = 2^2n instead of 2*2^n = 2^n+1. Thanks for the help, sorry about the algebra error.
 

Similar threads

  • · Replies 1 ·
Replies
1
Views
2K
Replies
7
Views
3K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 9 ·
Replies
9
Views
6K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K